The ${\mathrm{BF}}_3$ is a planar molecule whereas ${\mathrm{NF}}_3$ is pyramidal because:

1. $\mathrm{B}-\mathrm{F}$ bond is more polar than $\mathrm{N}-\mathrm{F}$ bond.

2. Boron atom is bigger than nitrogen atom.

3. Nitrogen is more electronegative than boron.

4. ${\mathrm{BF}}_3$ has no lone pair but ${\mathrm{NF}}_3$ has a lone pair of electrons.

The hybridization of orbitals of N atom in $N{O}_3^{-},<mspace\; width="1em"></mspace>N{O}_2^{+,\hspace{0.17em}}and<mspace\; width="1em"></mspace>N{H}_4^{+}$ are respectively:

1. $sp,<mspace\; width="1em"></mspace>s{p}^2,<mspace\; width="1em"></mspace>s{p}^3$

2. $s{p}^2,<mspace\; width="1em"></mspace>sp,<mspace\; width="1em"></mspace>s{p}^3$

3. $sp,<mspace\; width="1em"></mspace>s{p}^3,<mspace\; width="1em"></mspace>s{p}^2$

4. $s{p}^2,<mspace\; width="1em"></mspace>s{p}^3,<mspace\; width="1em"></mspace>sp$

The correct bond angle for \(\mathrm{sp}^2\) hybridization is:
1. \(90^\circ\)
2. \(120^\circ\)
3. \(180^\circ\)
4. \(109^\circ\)

The hybridization of nitrogen in ${\mathrm{NO}}_2^{+},$ ${\mathrm{NO}}_3^{-}$ and ${\mathrm{NH}}_4^{+}$ respectively is : 
1. sp, sp^3, and sp²
2. sp, sp^2, and sp³
3. sp², sp, and sp³
4. sp², sp^3, and sp

Xe F${}_2$ is isostructural with : 

1. ${\mathrm{SbCl}}_3$

2. ${\mathrm{BCl}}_3$

3. ${\mathrm{TeF}}_2$

4. ${\mathrm{ICl}}_2^{-}$

Among the following molecules/ions BF₃, NO₂^-, NH₂^- , and H₂O, the central atom is sp² hybridized in :  

1. NO₂^- and NH₂^-

2. NH₂^-  and H₂O

3. NO₂^- and H₂O

4. BF₃ and NO₂^-

XeF₂ is isostructural with : 

1. TeF₂

2. ICI₂^-

3. SbCl₃

4. BCl₃

In which of the following molecules/ions BF₃, ${\mathrm{NO}}_2^{-}$,  ${\mathrm{NH}}_2^{-,\hspace{0.17em}}$and H₂O, the central atom is sp² hybridized?

1. $N{O}_2^{-}$ $and$ $N{H}_2^{-}$

2. $N{H}_2^{-}$ $and$ $H_{2}O$

3. $N{O}_2^{-}$ $and$ $H_{2}O$

4. $B{F}_3$ $and$ $N{O}_2^{-}$

Isostructural pair among the following is:

1. ${\mathrm{BCl}}_3$ $\mathrm{and}$ ${\mathrm{BrCl}}_3$

2. ${\mathrm{NH}}_3$ $\mathrm{and}$ ${\mathrm{NO}}_3^{-}$

3. ${\mathrm{NF}}_3$ $\mathrm{and}$ ${\mathrm{BF}}_3$

4. ${\mathrm{BF}}_4^{-}$ $\mathrm{and}$ ${\mathrm{NH}}_4^{+}$

Given the following hydrocarbon:

The state of hybridisation of carbons marked 2, 3, 5 and 6 in the following hydrocarbon are, respectively :

1. sp, sp³, sp² and sp³

2. sp³, sp², sp² and sp

3. sp, sp², sp² and sp³

4. sp, sp² sp³ and sp²