Q. No.
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Molecule/Ion that is diamagnetic in nature is:
| 1. | \(\mathrm{H}^-_2\) | 2. | \(\mathrm{H}_2\) |
| 3. | \(\mathrm{H}^+_2\) | 4. | \(\mathrm{He}^+_2\) |
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In the option are given sequences of increasing bond order for the following species. The correct option is :
\(\mathrm{O}_2,\mathrm{N}_2,\mathrm{O}^+_2 ~\mathrm{and}~\mathrm{O}^-_2\)
| 1. | \(\mathrm{O}_2>\mathrm{N}_2>\mathrm{O}^+_2>\mathrm{O}^-_2\) | 2. | \(\mathrm{O}^-_2>\mathrm{O}_2>\mathrm{O}^+_2>\mathrm{N}_2\) |
| 3. | \(\mathrm{N}_2>\mathrm{O}^+_2>\mathrm{O}_2>\mathrm{O}^-_2\) | 4. | \(\mathrm{O}^-_2>\mathrm{O}^+_2>\mathrm{O}_2>\mathrm{N}_2\) |
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What is the correct sequence of bond order for the specified species?
| 1. | \(\mathrm{O}^-_2>\mathrm{O}_2>\mathrm{O}^+_2\) | 2. | \(\mathrm{O}^-_2<\mathrm{O}_2<\mathrm{O}^+_2\) |
| 3. | \(\mathrm{O}^-_2>\mathrm{O}_2<\mathrm{O}^+_2\) | 4. | \(\mathrm{O}^-_2<\mathrm{O}_2>\mathrm{O}^+_2\) |
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A pair in which both species are not likely to exist is:
| 1. | \(H^+_2,He^{2-}_2\) | 2. | \(H^-_2,He^{2+}_2\) |
| 3. | \(H^{2+}_2,He_2\) | 4. | \(H^+_2,He^{2+}_2\) |
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The bond order of 1.5 is shown by:
| 1. | \(\text O^+_2\) | 2. | \(\text O^-_2\) |
| 3. | \(\text O^{2-}_2\) | 4. | \(\text O_2\) |
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The relative order of stability of the following species: \(\mathrm{O}_2,\mathrm{O}^+_2,\mathrm{O}^-_2~\mathrm{and}~\mathrm{O}^{2-}_2\) is -
| 1. | \(\mathrm{O}^+_2>\mathrm{O}_2>\mathrm{O}^-_2>\mathrm{O}^{2-}_2\) | 2. | \(\mathrm{O}^{2-}_2>\mathrm{O}_2>\mathrm{O}^-_2>\mathrm{O}^{+}_2\) |
| 3. | \(\mathrm{O}_2>\mathrm{O}^+_2>\mathrm{O}^-_2>\mathrm{O}^{2-}_2\) | 4. | \(\mathrm{O}_2>\mathrm{O}^{2-}_2>\mathrm{O}^-_2>\mathrm{O}^{+}_2\) |
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In which of the following pairs of molecules/ions, the central atoms have \(\mathrm{sp}^2\) hybridisation?
| 1. | \(\mathrm{NO}^-_2 ~\mathrm{and}~ \mathrm{NH}_3\) | 2. | \(\mathrm{BF}_3 ~\mathrm{and}~ \mathrm{NO}^-_2\) |
| 3. | \(\mathrm{NH}^-_2 ~\mathrm{and}~ \mathrm{H_2O}\) | 4. | \(\mathrm{BF}_3 ~\mathrm{and}~ \mathrm{NH}^-_2\) |
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