The ionization constant of acetic acid is \(1.74 × 10^{–5}.\) The pH of acetic acid in its 0.05 M solution will be:
1. 7.81

2. 3.03

3. 8.54

4. 1.45

Subtopic:  Ionisation Constant of Acid, Base & Salt | pH calculation |
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Level 2: 60%+

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The ionization constant of propanoic acid is 1.32 × 10–5. The degree of ionization of 0.05M acid solution will be:

1. α = 0.63 × 10–2

2. α = 1.63 × 10–4

3. α = 1.63 × 10–2

4. α = 0.05 × 10–2

Subtopic:  Ionisation Constant of Acid, Base & Salt | pH calculation |
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The salt that gives a neutral solution in water is: 

1. KBr

2. NH4NO3

3. NaCN 4. Rb2(CO3)
Subtopic:  Salt Hydrolysis & Titration |
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Level 2: 60%+

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I2(s) + 5F2(g)  →2IF5(g) 

The equilibrium constant Kc expression for the above mentioned reaction is:
1. \(\mathrm{K_{C} = \dfrac{\left[IF_{5}\right]^{2}}{\left[F_{2}\right]^{5}}}\) 2. \(\mathrm{K_{C} = \dfrac{\left[IF_{5}\right]^{2}}{\left[F_{2}\right]^{5} \left[I_{2}\right]}}\)
3. \(\mathrm{K_{C} = \dfrac{\left[F_{2}\right]^{5} \left[I_{2}\right]}{\left[IF_{2}\right]^{2}}}\) 4. \(\mathrm{K_{C} = \dfrac{\left[F_{2}\right]^{5}}{\left[IF_{5}\right]^{2}}}\)
Subtopic:  Introduction To Equilibrium |
 81%
Level 1: 80%+

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The first ionization constant of H2S is 9.1 × 10–8. The concentration of HS– ion in its 0.1 M solution will be:

1. 12.3 × 10–7 M 2. 11.4 × 10–6 M
3. 3.5 × 10–4 M 4. 9.54 × 10–5 M
Subtopic:  Ionisation Constant of Acid, Base & Salt |
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The species described below that contain Lewis acids are:

O
H– , F– , H+ and BCl3


1. BCl3 and F–

2. OH– and F–

3. H+and BCl3

4. F– and BF3
Subtopic:  Acids & Bases - Definitions & Classification |
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What are the conjugate bases of the Brönsted acids \(\mathrm{H}_2 \mathrm{SO}_4\), and \(\mathrm{HCO}_3^{-}\) respectively?
1. \(\mathrm{HSO}_4^{-}, \mathrm{CO}_3^{2-}\)
2. \(\mathrm{HSO}_4^{-}, \mathrm{CO}_3^{-}\)
3. \(\mathrm{SO}_4^{2-}, \mathrm{CO}_3{ }^{2-}\)
4. \(\mathrm{HS}_2 \mathrm{O}_4{ }^{-}, \mathrm{CO}_3{ }^{2-}\)
Subtopic:  Acids & Bases - Definitions & Classification |
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Level 1: 80%+

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Find the effect of (i) increasing pressure and (ii) increasing temperature on Kc for the following equilibrium:

PCl₅(g) ⇌ PCl₃(g) + Cl₂(g)

ΔᵣH° = +124.0 kJ mol⁻¹
Kc = 8.3 × 10⁻³ mol L⁻¹ at 473 K

1. (i) Kc increases; (ii) Kc decreases
2. (i) Kc decreases; (ii) Kc remains unchanged
3. (i) Kc remains unchanged; (ii) Kc increases
4. (i) Kc remains unchanged; (ii) Kc decreases

Subtopic:  Kp, Kc & Factors Affecting them |
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(a) PCl5 (g) ⇋ PCl3 (g) + Cl2 (g)

(b) CaO (s) + CO2 (g) ⇋  CaCO3 (s)

(c) 3Fe (s) + 4H2O (g) ⇋ Fe3O4 (s) + 4H2 (g)

The effect of an increase in the volume on the number of moles of products in the above-mentioned reactions would be, respectively:

1. a) Increase,  b) decrease, c) same

2. a) Decrease,  b) same, c) increase

3. a) Increase,  b) increase, c) same

4. a) Increase,  b) decrease, c) increase

Subtopic:  Le Chatelier's principle |
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Level 2: 60%+

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What is the molarity of the standard solution if the solubility product for a salt of type AB is 4×10-8?

1. 2×10-4 mol/L

2. 16×10-16 mol/L

3. 2×10-16 mol/L

4. 4×10-4 mol/L

Subtopic:  Solubility Product |
 84%
Level 1: 80%+
NEET - 2020

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