The electronic configuration of Palladium is:
1. [Kr] 5f3 6d1 7s2
2. [Kr] 5f5 6d1 7s2
3. [Kr] 5f2 6d1 7s2
4. None of the above.
The formation of the oxide ion, O²⁻(g), from an oxygen atom occurs in two successive steps:
O(g) + e⁻ → O⁻(g) ΔH = −141 kJ mol⁻¹
O⁻(g) + e⁻ → O²⁻(g) ΔH = +780 kJ mol⁻¹
Although O²⁻ is isoelectronic with neon, its formation in the gaseous state is energetically unfavourable. What is the main reason for this?
| 1. | Electron repulsion outweighs the stability gained by achieving a noble gas configuration. |
| 2. | O– ion has a comparatively smaller size than the oxygen atom. |
| 3. | Oxygen is more electronegative. |
| 4. | Addition of electrons in oxygen results in a large size of the ion. |
1. Cr > Mn > V > Ti
2. V > Mn > Cr > Ti
3. Mn > Cr > Ti > V
4. Ti > V > Cr > Mn
Identify the correct order of the size of the following:
1.
2.
3.
4.
For the second-period elements, the correct increasing order of first ionisation enthalpy is:
| 1. | Li < Be < B < C < O < N < F < Ne |
| 2. | Li < Be < B < C < N < O < F < Ne |
| 3. | Li < B < Be < C < O < N < F < Ne |
| 4. | Li < B < Be < C < N < O < F < Ne |
The incorrect order of electronegativity is :
| 1. | Cl > S > P > Si | 2. | Si > Al > Mg > Na |
| 3. | F > Cl > Br > I | 4. | None of the above. |
The element having electronic configuration [Kr]4d104f14, 5s25p6, 6s2 belongs to:
1. s-block
2. p-block
3. d-block
4. f-block
The electronegativity of the following elements increases in the order:
1. C, N, Si, P
2. N, Si, C, P
3. Si, P, C, N
4. P, Si, N, C
The order of screening effect of electrons of s, p, d and f orbitals of a given shell of an atom on electrons in its outer shell is :
1. s > p > d > f
2. f > d > p > s
3. p < d < f < s
4. f > p > s > d
Which of the following groups of elements is characterized by the progressive filling of 4f orbitals?
| 1. | Actinoids | 2. | Transition elements |
| 3. | Lanthanoids | 4. | Halogens |