Consider the change in oxidation state of bromine corresponding to different emf values as shown in the diagram below:

The species undergoing disproportionation is:
| 1. | \(\text{BrO}^-_3\) | 2. | \(\text{BrO}^-_4\) |
| 3. | \(\text{Br}_2\) | 4. | \(\text{HBrO}\) |
Find the relationship between E₁ and E₂ for the following Daniell cell:
Zn | ZnSO₄ (0.01 M) || CuSO₄ (1.0 M) | Cu
The emf of this cell is E₁.
If the concentration of ZnSO₄ is changed to 1.0 M and that of CuSO₄ is changed to 0.01 M, the emf becomes E₂.
Given:
RT/F = 0.059 V
1. E1 = E2
2. E1 > E2
3. E1 < E2
4. E2 = 0 \(\neq\)E1