Consider the change in oxidation state of bromine corresponding to different emf values as shown in the diagram below: 
 

The species undergoing disproportionation is:

1. \(\text{BrO}^-_3\) 2. \(\text{BrO}^-_4\)
3. \(\text{Br}_2\) 4. \(\text{HBrO}\)
Subtopic:  Electrode & Electrode Potential |
 62%
Level 2: 60%+
NEET - 2018
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Find the relationship between E₁ and E₂ for the following Daniell cell:

Zn | ZnSO₄ (0.01 M) || CuSO₄ (1.0 M) | Cu

The emf of this cell is E₁.

If the concentration of ZnSO₄ is changed to 1.0 M and that of CuSO₄ is changed to 0.01 M, the emf becomes E₂.

Given:

RT/F = 0.059 V

1. E1 = E2

2. E1 > E2

3. E1 < E2

4. E2 = 0 \(\neq\)E1

Subtopic:  Electrode & Electrode Potential | Nernst Equation |
Level 4: Below 35%
NEET - 2017
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