| 1. | Both \(\Delta H\) and \(\Delta S\) are positive |
| 2. | \(\Delta H\) is negative but \(\Delta S\) is positive |
| 3. | \(\Delta H\) is positive but \(\Delta S\) is negative |
| 4. | Both \(\Delta H\) and \(\Delta S\) are negative |
| ΔH | ΔS | Temperature | Spontaneity | |
| (A) | + | - | any T | Spontaneous |
| (B) | + | + | low T | Non spontaneous |
| (C) | - | - | low T | Spontaneous |
| (D) | - | + | any T | Non spontaneous |
| 1. | 2750 | 2. | 2850 |
| 3. | 2875 | 4. | 2900 |
| Column I | Column II | ||
| (i) | Spontaneous process | (a) | Isothermal and isobaric process |
| (ii) | \(\Delta H^\circ\) | (b) | \(\Delta H<0 \) |
| (iii) | \(\Delta T=0, \Delta P=0 \) | (c) | \(\Delta G<0 \) |
| (iv) | Exothermic process | (d) | (Bond energy of reactant) - (Bond energy of product) |
| I | II | III | IV | |
| 1. | c | d | a | b |
| 2. | b | a | c | d |
| 3. | d | b | c | d |
| 4. | a | d | b | c |
Assuming ideal behaviour, for the reaction
3HC≡CH(g) ⇌ C₆H₆(l)
at 25°C, the magnitude of log K is expressed as x × 10⁻¹. Calculate the value of x.
Given:
ΔfG°(HC≡CH) = −2.04 × 10⁵ J mol⁻¹
ΔfG°(C₆H₆) = −1.24 × 10⁵ J mol⁻¹
R = 8.314 J K⁻¹ mol⁻¹
1. 860
2. 875
3. 855
4. 895
Calculate the minimum temperature at which the following reaction becomes spontaneous:
FeO(s) + C(graphite) → Fe(s) + CO(g)
Given:
ΔHf°(FeO) = –266.3 kJ mol⁻¹
ΔHf°(C) = 0
ΔHf°°(Fe) = 0
ΔHf°(CO) = –110.5 kJ mol⁻¹
ΔS°(FeO) = 57.49 J mol⁻¹ K⁻¹
ΔS°(C) = 5.74 J mol⁻¹ K⁻¹
ΔS°(Fe) = 27.28 J mol⁻¹ K⁻¹
ΔS°(CO) = 197.6 J mol⁻¹ K⁻¹
Consider the following cell reaction:
Cd(s) + Hg₂SO₄(s) + (9/5)H₂O(l) ⇌ CdSO₄·(9/5)H₂O(s) + 2Hg(l)
At 25°C, E°cell = 4.315 V and ΔH° = −825.2 kJ mol⁻¹
Calculate the standard entropy change, ΔS°, for the reaction.
Given: F = 96487 C mol⁻¹
1. 25.1 J K⁻¹mol-1
2. 29.1 J K⁻¹mol-1
3. 45.1 J K⁻¹mol-1
4. 67.6 J K⁻¹mol-1