- 1(current)
Q. No.Two identical charged conducting spheres \(A\) and \(B\) have their centres separated by a certain distance. Charge on each sphere is \(q\) and the force of repulsion between them is \(F. \) A third identical uncharged conducting sphere is brought in contact with sphere \(A\) first and then with \(B \) and finally removed from both. New force of repulsion between spheres \( A\) and \(B \) (Radii of \(A\) and \(B \) are negligible compared to the distance of separation so that for calculating force between them they can be considered as point charges) is best given as:
| 1. | \(\dfrac{F}{2}\) | 2. | \(\dfrac{3 F}{8}\) |
| 3. | \(\dfrac{3 F}{5}\) | 4. | \(\dfrac{2 F}{3}\) |
Subtopic: Â Coulomb's Law |
 65%
Level 2: 60%+
NEET - 2025
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The ratio of Coulomb's electrostatic force to the gravitational force between an electron and a proton separated by some distance is \(2.4\times 10^{39}.\) The ratio of the proportionality constant, \(k=\dfrac{1}{4\pi\varepsilon_0}\) to the gravitational constant \(G\) is nearly:
(Given that the charge of the proton and electron each \(=1.6\times 10^{-19},\) the mass of the electron \(=9.11\times 10^{-31}~\text{kg},\) the mass of the proton \(=1.67\times 10^{-27}~\text{kg}\) )
(Given that the charge of the proton and electron each \(=1.6\times 10^{-19},\) the mass of the electron \(=9.11\times 10^{-31}~\text{kg},\) the mass of the proton \(=1.67\times 10^{-27}~\text{kg}\) )
| 1. | \(10^{20}\) | 2. | \(10^{30}\) |
| 3. | \(10^{40}\) | 4. | \(10\) |
Subtopic: Â Coulomb's Law |
 62%
Level 2: 60%+
NEET - 2022
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The acceleration of an electron due to the mutual attraction between the electron and a proton when they are \(1.6~\mathring{A}\) apart is:
\(\left(\dfrac{1}{4 \pi \varepsilon_0}=9 \times 10^9~ \text{Nm}^2 \text{C}^{-2}\right)\)
1. \( 10^{24} ~\text{m/s}^2\)
2. \( 10^{23} ~\text{m/s}^2\)
3. \( 10^{22}~\text{m/s}^2\)
4. \( 10^{25} ~\text{m/s}^2\)
Subtopic: Â Coulomb's Law |
 76%
Level 2: 60%+
NEET - 2020
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Two point charges \(A\) and \(B,\) having charges \(+Q\) and \(-Q\) respectively, are placed at a certain distance apart and the force acting between them is \(F.\) If \(25\%\) charge of \(A\) is transferred to \(B,\) then the force between the charges becomes:
| 1. | \(\frac{4F}{3}\) | 2. | \(F\) |
| 3. | \(\frac{9F}{16}\) | 4. | \(\frac{16F}{9}\) |
Subtopic: Â Coulomb's Law |
 79%
Level 2: 60%+
NEET - 2019
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- 1(current)
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