As an isolated box, equally partitioned, contains two ideal gasses A and B as shown:

 

When the partition is removed, the gases mix. The changes in enthalpy (∆H) and entropy (∆S) in the process, respectively, are

1. Zero, positive

2. Zero, negative

3. Positive, zero

4. Negative, zero

Subtopic:  Enthalpy & Internal energy |
 81%
Level 1: 80%+
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The ∆H for vaporization of a liquid is \(20 \mathrm{~kJ} / \mathrm{mol}.\) Assuming ideal behaviour, the change in internal energy for the vaporization of \(1 \mathrm{~mol}\) of the liquid at \(60^{\circ} \mathrm{C}\) and 1 bar is close to:

1. \(13.2 \mathrm{~kJ} / \mathrm{mol} \) 2. \(17.2 \mathrm{~kJ} / \mathrm{mol} \)
3. \(19.5 \mathrm{~kJ} / \mathrm{mol} \) 4. \(20.0 \mathrm{~kJ} / \mathrm{mol}\)
Subtopic:  Enthalpy & Internal energy |
 71%
Level 2: 60%+
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What is the amount of work done by an ideal gas, if the gas expands isothermally from \(10^{-3}~m^3\) to \(10^{-2}~m^3\) at \(300~K\)against a constant pressure of \(10^{5}~Nm^{-2}\)?

1. \(+270 ~kJ\) 2. \(–900 ~J\)
3. \(+900 ~kJ\) 4. \(–900~ kJ\)
Subtopic:  First Law of Thermodynamics |
 72%
Level 2: 60%+
NEET - 2019
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∆Hf0 (298K) of methanol is given by the chemical equation:

1. \(\mathrm{C}(\text { diamond })+\frac{1}{2} \mathrm{O}_{2(\mathrm{~g})}+2 \mathrm{H}_{2(\mathrm{~g})} \rightarrow \mathrm{CH}_3 \mathrm{OH}_{(\mathrm{l})}\)

2. \(\mathrm{CH}_{4(\mathrm{~g})}+\frac{1}{2} \mathrm{O}_{2(\mathrm{~g})} \rightarrow \mathrm{CH}_3 \mathrm{OH}_{(\mathrm{g})}\)

3. \(\mathrm{CO}_{(\mathrm{g})}+2 \mathrm{H}_{2(\mathrm{~g})} \rightarrow \mathrm{CH}_3 \mathrm{OH}_{(\mathrm{l})}\)

4. \(\mathrm{C}(\text { graphite })+\frac{1}{2} \mathrm{O}_{2(\mathrm{~g})}+2 \mathrm{H}_{2(\mathrm{~g})} \rightarrow \mathrm{CH}_3 \mathrm{OH}_{(\mathrm{l})}\)

Subtopic:  Thermochemistry |
 78%
Level 2: 60%+
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On complete combustion, 4.8 g of diamond releases 158.4 kJ of heat. The standard enthalpy of formation of gaseous carbon is 725 kJ mol⁻¹. Calculate the energy required for the following process:
(Given - Heat of combustion of graphite is −394 kJ mol⁻¹.)

(i) C(graphite)→C(gas)

(ii) C(diamond)→C(gas)

1. 725, 727 2. 727, 725
3. 725, 723 4. None of the above
Subtopic:  Hess's Law |
Level 3: 35%-60%
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A piston filled with 0.04 mol of an ideal gas expands reversibly from 50.0 mL to 375 mL at a constant temperature of 37.0ºC. As it does so, it absorbs 208 J of heat. The values of q and w for the process will be-
(R = 8.314 J/mol K) (ln 7.5 = 2.01)

1. q = +208 J, w = -208 J 2. q = -208 J, w = -208 J
3. q = -208 J, w = + 208 J 4. q = +208 J, w = + 208 J
Subtopic:  First Law of Thermodynamics |
 83%
Level 1: 80%+
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The standard enthalpy of combustion at 25∘C of hydrogen, cyclohexene (C6H10), and cyclohexane (C6H12) are -241, -3800 and -3920 kJ mol-1, respectively. Calculate the standard enthalpy of hydrogenation of cyclohexene.

1. -121 kJ mol-1 2. -155 kJ mol-1
3. -167 kJ mol-1 4. -131 kJ mol-1
Subtopic:  Thermochemistry |
Level 4: Below 35%
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An ideal gas is expanded irreversibly against 10 bar pressure from 20 litres to 30 litres. Calculate 'w' if the process is isoenthalpic.

1. 0 2. +100J
3. -100 J 4. -10 kJ
Subtopic:  First Law of Thermodynamics |
Level 3: 35%-60%
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Entropy decreases during:

1. Crystallization of sucrose from solution

2. Rusting of iron

3. Melting of ice

4. Vaporization of camphor

Subtopic:  Spontaneity & Entropy |
 85%
Level 1: 80%+
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At a temperature of 300K, what is the entropy change for the reaction given below?

2H2 (g) + O2 (g) →2H2O(l)

Standard entropies of H2 (g), O2(g) and H2O(l) are 126.6, 201.20 and 68.0 JK-1mol-1 respectively.

1. -318.4 JK-1mol-1                           

2. 318.4 JK-1mol-1 

3. 31.84 JK-1mol-1                             

4. None of the above

Subtopic:  Spontaneity & Entropy |
 82%
Level 1: 80%+
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