Find the energy absorbed per mole of photons according to the law of photochemical equivalence using:
E = Nₐhc/λ
Given:
h = 6.62 × 10⁻²⁷ erg s
c = 3 × 10¹⁰ cm s⁻¹
Nₐ = 6.02 × 10²³ mol⁻¹
| 1. | \({{1.196\times 10^{8}}\over{\lambda}}\) | 2. | \({{2.859\times 10^{5}}\over{\lambda}}\) |
| 3. | \({{2.859\times 10^{16}}\over{\lambda}}\) | 4. | \({{1.196\times 10^{16}}\over{\lambda}}\) |