NEET Physics Nuclei Questions Solved


If the binding energy of the deutrium is 2.23 MeV.
The mass defect given in a.m.u. is 
(a) – 0.0024             (b) – 0.0012
(c) 0.0012                (d) 0.0024

(d) Mass defect m=2.23931 = 0.0024.

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