Go through the following diagram of Nucleosome (structural unit of chromatin). Identify its componential parts indicated by A, B and C:

 

A

B

C

(a)

RNA

Non histone

Histone

(b)

DNA

H1 histone

Histone Octamer

(c)

RNA

Histone Octamer

H1 histone

(d)

DNA

Non histone

Histone

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Following is the schematic structure of transcription unit having some important components indicated by A, B, C, D and E. In which of four option the components are identified correctly:

 

A

B

C

D

E

(a)

Terminator

Transcription start site

Promoter

Template strand

Coding strand

(b)

Promoter

Transcription start site

Terminator

Coding strand

Template strand

(c)

Promoter

Transcription start site

Terminator

Template strand

Coding strand

(d)

Terminator

Transcription start site

Promoter

Coding strand

Template strand

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The fact that the genetic code is almost universal in living organisms is considered to be evidence that all organisms:
(a) Are evolutionarily related
(b) Are genetically identical
(c) Have the same sequence of anticodons
(d) None of the above

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In the following diagram of the lac operon, an operon for inducible enzymes, identify components and enzymes:

 

X

Y

E1

E2

E3

(a)

Repressor protein

Inducer (lactose)

â-Galactosidase

Permease

Transacetylase

(b)

Inducer (lactose)

Repressor protein

â-Galactosidase

Permease

Transacetylase

(c)

Repressor protein

Inducer (lactose)

â-Galactosidase

Transacetylase

Permease

(d)

Repressor protein

Inducer (lactose)

Permease

Transacetylase

â-Galactosidase

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Alfred Hershey and Martha Chase made a big contribution in proving DNA role as the hereditary molecule. The experiment is shown in the diagram. A and C are the presence or absence of radioactivity detected in cells B and D are the presence or absence of radioactivity detected in supernatants cells. Identify A, B, C and D:

(a) A - No Radioactivity (35S) detected in cells; B - Radioactivity (32P) detected in supernatant; C - Radioactivity (35S) detected in cells; D - No Radioactivity in supernatant
(b) A- Radioactivity (35S) detected in cells; B - No Radioactivity (35S) detected in supernatant; C - Radioactivity (32P) detected in cells; D - No Radioactivity in supernatant
(c) A - No Radioactivity (35S) detected in cells; B - Radioactivity (35S) detected in supernatant; C - Radioactivity (32P) detected in cells; D - No Radioactivity in supernatant
(d) A - No Radioactivity (35S) detected in cells; B - Radioactivity (35S) detected in supernatant; C - No Radioactivity (32P) detected in cells; D - Radioactivity in supernatant

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If the DNA of this virus was labeled with 32P and the protein of the virus was labeled with 35S, which molecule(s) would be present inside the cells?
(a) 35S and 32P
(b) 35S only
(c) 32P only
(d) Neither molecule would be present inside the cell

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Which of the following statements is correct?
I. The biochemical nature of genetic material was not defined from the experiments conducted by Griffith
II. Working on transformation Avery et al concluded DNA is genetic material but not all biologists were convinced
III. RNA is the genetic material in TMV, QB bacteriophage etc.
IV. DNA is the predominant genetic material while RNA performs dynamic functions of messenger adapter
V. Viruses having DNA genome and having shorter life span mutate and evolve faster
(a) All are correct             (b) I and II              (c) All except V                (d) III and IV

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The prediction of sequence of amino acid is _____A ____ if the sequence of nucleotides mRNA is known. The prediction of sequence of nucleotide is concerned mRNA is ____B____ because the genetic code is _____C_____:
(a) A - possible, B - impossible, C - universal
(b) A - possible, B - impossible, C - degenerate
(c) A - impossible, B - possible, C - universal
(d) A - impossible, B - possible, C - degenerate

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Choose the correct statements:
I. Binding of mRNA to the ribosome is loose and reversible.
II. The ribosome, which is composed of tRNA and proteins, consists of a small and large subunit.
III. Each of the 20 amino acids has a minimum of one specific tRNA molecule.
IV. tRNAMET binds to the first codon (AUG) - this is called the START codon.
V. The second tRNA binds to the second codon so that their attached monosaccharides are next to each other
VI. The newly formed polypeptide may undergo post-transcriptional modification.
(a) I, III and IV         (b) II, IV, VI               (c) II, V and VI           (d) I, V, VI

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The length of DNA has 45000 base pairs. How many complete turns will the DNA molecule take?

(a) 45000             (b) 450                 (c) 4500                (d) 45

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