# NEET Questions Solved

AIIMS - 2001

A cell whose e.m.f. is 2 V and internal resistance is 0.1 Ω, is connected with a resistance of 3.9 Ω. The voltage across the cell terminal will be

(1) 0.50 V

(2) 1.90 V

(3) 1.95 V

(4) 2.00 V

(3) The voltage across cell terminal will be given by

$=\frac{E}{R+r}×R=\frac{2}{\left(3.9+0.1\right)}×3.9=1.95V$

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