Why does the reaction produce stable salt?

Because
1. In 'A' the ring is aromatic
2. 6 p electrons are present
3. Ring in a is stabilized by closed-loop conjugation
4. All of these
The major product of reaction

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| (2) | ![]() |
| (3) | ![]() |
| (4) | ![]() |
The end product of the folloowing reaction sequence is:

| (1) | ![]() |
| (2) | ![]() |
| (3) | ![]() |
| (4) | ![]() |
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The compound 'C' is
1. PhCH(OH)CHO
2. PhCH(OH)COOH
3. 
4. 
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The product/s of the following reaction is


| (1) | ![]() ![]() |
| (2) | ![]() ![]() |
| (3) | ![]() ![]() |
| (4) | ![]() ![]() |
Which step is not feasible in the following loop?

(1) step – a
(2) step – b
(3) step – c
(4) step – d

The product R is :
| (1) | ![]() |
| (2) | ![]() |
| (3) | ![]() |
| (4) | ![]() |

The product 'C' is
| (1) | ![]() |
| (2) | ![]() |
| (3) | ![]() |
| (4) | ![]() |
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The product B is
(1) PhCH = CHCH2Br
(2) ![]()
(3) PhCH2CH(Br)COOH
(4) PhCH = CH − Cobr
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| 2. | ![]() |
| 3. | ![]() |
| 4. | ![]() |
The number of stereoisomeric products formed in the following reaction is

(1) 1
(2) 8
(3) 4
(4) 2