The compound A and B respectively are:

1.		2.
3.		4.

The final compound 'B' in the below reaction is:

1.		2.
3.		4.

Alkyl isocyanide on hydrolysis produces: 

In the below-mentioned reaction, the major product (A) formed is:

 

1.		2.
3.		4.	None of these

$\stackrel{{\left({\mathrm{NH}}_4\right)}_2\mathrm{S}}{\to }A\underset{0-5°C}{\overset{NaN{O}_2/HCl}{\to }}B\underset{∆}{\overset{C_2{H}_{5}OH}{\to }}\mathrm{C<mspace\; width="1em"></mspace><mspace\; width="1em"></mspace>}$

Product (C) is  

1. Nitrobenzene

2. 1,3-Diethoxybenzenez

3. Ethoxybenzene

4. Benzene

Reaction of $\mathrm{R}-\stackrel{\mathrm{O}}{\stackrel{\left|\right|}{\mathrm{C}}}-{\mathrm{NH}}_2$ with a mixture of Br₂ and KOH gives R-NH₂ as the main product. The intermediates involved in this reaction are: 

1. $\mathrm{R}-\stackrel{\mathrm{O}}{\stackrel{\left|\right|}{\mathrm{C}}}-\mathrm{NHBr}<mspace\; width="1em"></mspace>\mathrm{and}<mspace\; width="1em"></mspace>\mathrm{R}-\mathrm{N}=\mathrm{C}=\mathrm{O}$

2. RCN

3. $\mathrm{R}-\stackrel{\mathrm{O}}{\stackrel{\left|\right|}{\mathrm{C}}}-{\mathrm{NBr}}_2$

4. RNHBr

The major product of the following reaction would be

1.
2.
3.
4.

In the above reaction the product will be

1.
2.
3.
4.

C (major product) is

1.
2.
3.
4.	None of the above