2Ag(aq) + Cu(s)            Cu(aq)+2 + 2Ag(s)

The cell potential for this reaction is 0.46V. Which of the following change will increase the potential the most ?

(1) [Ag] concentration is doubled

(2) [Cu2+] concentration is halved

(3) Size of Cu(s) electrode is doubled

(4) size of Ag(s) electrode is decreased to half

Subtopic:  Electrochemical Series |
 73%
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What will be the value of G° for the rection Cu+2 + Fe             Fe+2 + Cu , 

if ECu+2Cu = +0.34 V and EFe+2Fe = -0.44 V

(1) -65.62 KJ

(2) -75.27 KJ

(3) -150.54 KJ

(4) +150.54 KJ

Subtopic:  Electrode & Electrode Potential |
 77%
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At 298 K the Emf of the following cell is:-

\(\small{Pt|H_{2}(1 \ atm)|H^{+}(0.02 \ M) \ || \ H^{+}(0.01 \ M)|H_{2}(1 \ atm)|Pt}\)

1. - 0.017 V

2. 0.0295 V

3. 0.1 V

4. 0.059 V

Subtopic:  Nernst Equation |
 58%
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At 25°C temperature Zn electrode is placed in 0.1M solution of zinc salt then what will be the reduction potential ? If it is assumed that salt dissociates 25% at this dilution (EZn2+Zn° = -0.76 V)

(1) -0.713 V

(2) - 0.81 V

(3) + 0.778 V

(4) - 0.84 V

Subtopic:  Nernst Equation |
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The reduction potential of Hydrogen electrode is -118mV then the concentration of Hion in solution will be :-

(1) 10-4M

(2) 2M

(3) 0.01M

(4) 10-3M

Subtopic:  Nernst Equation |
 62%
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The maximum work which can be obtained from a Daniel cell \(Zn_{(s)}\ |\ Zn^{+2}_{(aq)}\ || Cu^{+2}_{(aq)}\ |\ Cu_{(s)}\) is:

\(E^o_{Zn^{2+}/Zn}\) −0.76 V
\(E^o_{Cu^{2+}/Cu}\) 0.34 V

1. 106.15 kJ

2. -212.3 kJ

3. 424.6 kJ

4. +212.3 kJ

Subtopic:  Electrode & Electrode Potential |
 60%
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CuSO4 solution is treated separately with KCl and KI. In which case, Cu+2 will be reduced to Cu ?

(1) with KCl

(2) with KI

(3) with KCl and KI both

(4) None of these

Subtopic:  Electrode & Electrode Potential |
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How many coulombs are required to oxidise 1 mol H2O2 to O2 ?

(1) 9.65 X 104 C

(2) 9.3 X 104 C

(3) 1.93 X 105 C

(4) 19.3 X 102 C

Subtopic:  Faraday’s Law of Electrolysis |
 62%
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The quantity of electricity required to reduce 12.3 g of nitrobenzene to aniline with 50 % current efficiency is:

1. 1 F

2. 0.6 F

3. 0.5 F

4. 1.2 F

Subtopic:  Faraday’s Law of Electrolysis |
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Electrolysis of hot aqueous solution of NaCl gives NaClO4 as-

NaCl +4H2O           NaClO4 + 4H2

How many faraday are required to obtain 1000 g of sodium perchlorate ?

(1) 66 F

(2) 122.5 F

(3) 15.13 F

(4) 1.86 F

Subtopic:  Faraday’s Law of Electrolysis |
 59%
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