A car travelling at a speed of 30 km/h is brought to rest at a distance of 8 m by applying brakes. If the same car is moving at a speed of 60 km/h, then it can be brought to rest with the same brakes in:

1. 64 m

2. 32 m

3. 16 m

4. 4 m

A particle is thrown with any velocity vertically upward, the distance travelled by the particle in the first second of its descent is:

(1) g

(2) $\frac{g}{2}$

(3) $\frac{g}{4}$

(4) Cannot be calculated

A body is thrown vertically upwards and takes 5 seconds to reach maximum height. The distance traveled by the body will be the same in

(1) 1^st and 10^th second

(2) 2^nd and 8^th second

(3) 4^th and 6^th second

(4) Both (2) & (3)

A ball is dropped from a bridge of 122.5 metre above a river. After the ball has been falling for two seconds, a second ball is thrown straight down after it. Initial velocity of the second ball so that both hit the water at the same time is

(1) 49 m/s

(2) 55.5 m/s

(3) 26.1 m/s

(4) 9.8 m/s

A balloon starts from the ground from rest with an upward acceleration of 2 m/s². After 1 sec, a stone is dropped from it. The time taken by the stone to strike the ground is approximately:

1. 0.3 s

2. 0.7 s

3. 1 s

4. 1.4 s

A boy throws balls into the air at a regular interval of 2 seconds. The next ball is thrown when the velocity of the first ball is zero. How high do the ball rise above his hand? [Take g = 9.8 m/ s²]

(1) 4.9 m

(2) 9.8 m

(3) 19.6 m

(4) 29.4 m

A ball projected from the ground vertically upward is at the same height at time t₁ and t₂. The speed of projection of ball is [Neglect the effect of air resistance]

(1) $g\left[t_2-t_1\right]$

(2) $\frac{g\left[t_1+t_2\right]}{2}$

(3) $\frac{g\left[t_2-t_1\right]}{2}$

(4) $g\left[t_1+t_2\right]$

Two balls are projected upward simultaneously with speeds of 40 m/s and 60 m/s. Relative position (x) of the second ball with respect to the first ball at time t = 5 sec will be: [Neglect air resistance]

1. 20 m

2. 80 m

3. 100 m

4. 120 m

A ball is dropped from a height h above ground. Neglect the air resistance, its velocity (v) varies with its height y above the ground as

(1) $\sqrt{2g(h-y)}$

(2) $\sqrt{2gh}$

(3) $\sqrt{2gy}$

(4) $\sqrt{2g(h+y)}$

For a body moving with uniform acceleration along the straight line, the variation of its velocity (v) with position (x) is best represented by:

(1) 

(2) 

(3) 

(4)