An oblique projectile is projected with a speed u. It takes time t, to reach the maximum height and time t, to come back to the ground. Air resistance is not neglected, then $\frac{{\mathrm{t}}_1}{{\mathrm{t}}_2}$ is

(1) > 1

(2) < 1

(3) = 1

(4) Depends on the angle of projection

The speed of a projectile projected from level ground at its maximum height is found to be half of its speed of projection (u). Its maximum height is:

1.  $\frac{3{\mathrm{u}}^2}{8\mathrm{g}}$

2.  $\frac{3{\mathrm{u}}^2}{2\mathrm{g}}$

3.  $\frac{\sqrt{3}{\mathrm{u}}^2}{2\mathrm{g}}$

4.  $\frac{3{\mathrm{u}}^2}{4\mathrm{g}}$

A body moved along x-axis and y-axis according to the equation,

$x=2\sin \theta$
$y=3\cos \theta$

What is the trajectory followed by the body?

1.  

2.  

3.  

4.  

A particle of mass \(m\) is projected with a velocity at an angle with the horizontal into a uniform gravitational field. The slope of the trajectory varies with horizontal distance \(x\) as:

1.		2.
3.		4.

A projectile thrown at an angle 30° with horizontal from the level ground reaches a maximum height of 20 m. What will be the maximum height if it is thrown at an angle 60° with the same speed?

(1) 20 m

(2) 30 m

(3) 50 m

(4) 60 m

A body moving in a uniform circular motion with speed v. The magnitude of the change in its velocity after it rotates by an angle 120° is:
1. \(2v\)
2. \(\sqrt{3}v\)
3. \(v\)
4. \(\frac{\sqrt{3}}{2}v\)

A car moves on a circular path such that its speed is given by v = Kt, where K =constant and t is time. Also given: radius of the circular path is r. The net acceleration of the car at time t will be:

1. $\sqrt{{\mathrm{K}}^2 + {\left(\frac{{\mathrm{K}}^2{\mathrm{t}}^2}{\mathrm{r}}\right)}^2}$

2. 2K

3. K

4. $\sqrt{{\mathrm{K}}^2 + {\mathrm{K}}^2{\mathrm{t}}^2}$

An object of mass 10 kg is projected from level ground with speed 40 m/s at angle 30° with horizontal. The rate of change of momentum of object [in SI units] 1 second after the projection is [neglect air resistance]

(1) 100

(2) 50

(3) 25

(4) 75

A particle is projected horizontally with speed 20 m/s from a cliff of height 20 m. The magnitude of the velocity of particle when it reaches the ground

1. 20 m/s

2. 40 m/s

3. 20$\sqrt{2}$ m/s

4. Zero

A projectile is thrown with an initial velocity of 20 m/s at an angle of 60° with horizontal, then the angle of the velocity of the projectile with horizontal after time 0.732 sec is:

(1) 45°

(2) 30°

(3) 0°

(4) 15°