Consider the spectral line resulting from transition \(n=2\) to \(n = 1\) in the atoms and ions given below.  The shortest wavelength is given by:

1. hydrogen atom
2. deuterium
3. singly ionised helium
4. doubly ionised lithium

Subtopic:  Spectral Series |
 56%
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An α-particle of energy 5 MeV is scattered through 180° by a fixed uranium nucleus. The distance of closest approach is of the order

1. 10-10 m 

2. 10-13 m 

3. 10-14 m 

4. 10-16 m

Subtopic:  Various Atomic Models |
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The energy of an electron in an excited hydrogen atom is -3.4 eV.  Its angular momentum will be:
(h = 6.626 × 10-34 J-s)

1. 1.11 × 1034 J s 

2. 1.51 ×10-31 J s

3. 2.11 × 10-34 J s

4. 3.72 × 10-34 J s

Subtopic:  Bohr's Model of Atom |
 70%
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The wavelength of Ka X-rays produced by an X-ray tube is 0.76 A. Find the atomic number of the anode material of the tube?

1. 41

2. 30

3. 20

4. 10

Subtopic:  X-Ray (OLD NCERT) |
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Energy levels A, B, C of a certain atom correspond to increasing values of energy i.e. EA<EB<EC. If λ1, λ2, λ3 are the wavelengths of the radiation corresponding to the transitions C to B, B to A and C to A respectively, which of the following relation is correct?

1. λ3=λ1+λ2 

2. λ3=λ1λ2λ1+λ2

3. λ1+λ2+λ3=0 

4. λ32=λ12+λ22

Subtopic:  Spectral Series |
 77%
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The velocity of the electron in the ground state (H - atom) is 

1. 2.18×105 m/s   

2. 2.18×106 m/s

3. 2.18×107 m/s   

4. 2.18×108 m/s

Subtopic:  Various Atomic Models |
 75%
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Which of the following transitions gives photon of maximum energy?

1. n = 1 to n = 2 

2. n = 2 to n = 1

3. n = 2 to n = 6 

4. n = 6 to n = 2

Subtopic:  Bohr's Model of Atom |
 62%
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When electron jumps from n = 4 to n = 2 orbit, we get [2000]

1. second line of Lyman series

2. second line of Balmer series

3. second line of Paschen series

4. an absorption line of Balmer series

Subtopic:  Spectral Series |
 83%
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In terms of Bohr radius a0, the radius of the second Bohr orbit of a hydrogen atom is given by [1992]

1. 4a0 

2. 8a0 

3. 2a0     

4. 2a0

Subtopic:  Bohr's Model of Atom |
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A diatomic molecule is made of two masses m1 and m2 which are separated by a distance r.  If we calculate its rotational energy by applying Bohr's rule of angular momentum quantization, its energy will be given by (n is an integer):

1. m1+m22n2h22m12m22r2     

2. n2h22π2(m1+m2)r2

3. 2n2h2(m1+m2)r2   

4. m1+m2n2h28π2m1m2r2

Subtopic:  Bohr's Model of Atom |
 52%
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