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#3 -Instantaneous-Velocity--Speed

(Physics) > Motion in A Plane

Related Practice Questions :

In 1.0 *s*, a particle goes from point *A* to point *B*, moving in a semicircle of radius 1.0 *m* (see figure). The magnitude of the average velocity is

(1) 3.14 *m*/*s*

(2) 2.0 *m*/*s*

(3) 1.0 *m*/*s*

(4) Zero

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The coordinates of a moving particle at any time ‘*t*’ are given by *x* = *αt*^{3} and *y* = *βt*^{3}. The speed of the particle at time ‘*t*’ is given by

(1) $\sqrt{{\alpha}^{2}+{\beta}^{2}}$

(2) $3\text{\hspace{0.17em}}t\sqrt{{\alpha}^{2}+{\beta}^{2}}$

(3) $3\text{\hspace{0.17em}}{t}^{2}\sqrt{{\alpha}^{2}+{\beta}^{2}}$

(4) ${t}^{2}\sqrt{{\alpha}^{2}+{\beta}^{2}}$

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Two particles having position vectors $\overrightarrow{{r}_{1}}=(3\hat{i}+5\hat{j})$ *metres* and $\overrightarrow{{r}_{2}}=(-5\hat{i}-3\hat{j})$ *metres* are moving with velocities ${\overrightarrow{v}}_{1}=(4\hat{i}+3\hat{j})\text{\hspace{0.17em}}m/s$ and ${\overrightarrow{v}}_{2}=(\alpha \text{\hspace{0.17em}}\hat{i}+7\hat{j})$ *m*/*s*. If they collide after 2 seconds, the value of ‘α’ is-

(1) 2

(2) 4

(3) 6

(4) 8

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A particle is moving such that its position coordinates (x, y) are (2m, 3m) at time t=0, (6m, 7m) at time t=2s and (13m, 14m) at time t=5s. Average velocity vector (v_{av}) from t=0 to t=5s is

(a)$\frac{1}{5}$(13$\hat{i}$+14$\hat{j}$)

(b)$\frac{7}{3}$($\hat{i}$+$\hat{j}$)

(c)2($\hat{i}$+$\hat{j}$)

(d)$\frac{11}{5}$($\hat{i}$+$\hat{j}$)

NEET - 2014

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