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#9 | Principle of Vernier Caliper

(Physics) > Units and Measurement

Related Practice Questions :

In a vernier calliper N divisions of vernier scale coincides with N-1 divisions of main scale (in which length of one division is 1 mm). The least count of the instrument should be

(A) $\mathrm{N}\mathrm{mm}$

(B) $\mathrm{N}-1\mathrm{mm}$

(C) $\frac{1}{10\mathrm{N}}\mathrm{cm}$

(D) $\frac{1}{\mathrm{N}-1}\mathrm{mm}$

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In certain vernier callipers 25 divisions on vernier scale have same length as 24 divisions on main scale. One division on main scale is 1 mm long. The least count of the instrument is

(A) 0.04 mm

(B) 0.01 mm

(C) 0.02 mm

(D) 0.08 mm

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One centimeter on the main scale of Vernier calliper is divided into ten equal parts. If 10 divisions of Vernier scale coincide with 8 small divisions of the main scale, the least count of the callipers is:

(A) 0.01 cm

(B) 0.02 cm

(C) 0.05 cm

(D) 0.07 cm

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If a screw gauge has a pitch of 1.5 mm and 300 divisions on circular scale, which of the following reading can be made from this screw gauge?

(A) 1.05 mm

(B) 3.01 cm

(C) 0.030000 m

(D) 2.1185 dm

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A Screw Guage gives the following readings when used to measure the diameter of a wire.

Main scale reading = 0mm

Circular scale reading = 52 divisions

Given that: 1 mm on main scale corresponds to 100 divisions of the circular scale.

The diameter of wire from the above data is:

(A) 0.026 cm

(B) 0.005 cm

(C) 0.52 cm

(D) 0.052 cm

AIEEE - 2011

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