In the diagram, a \(100\) kg block is moving up with constant velocity. Find out the tension at the point \(P\).

1. \(1330\) N
2. \(490\) N
3. \(1470\) N
4. \(980\) N
A lift is going up. The total mass of lift and the passenger is \(1500\) kg. The variation in the speed of the lift is as given in the graph. The tension in the rope pulling the lift at \(t=11^{\text{th}}\) s will be:
1. \(17400\) N
2. \(14700\) N
3. \(12000\) N
4. zero
A body is moving with a velocity of \(2\hat i\) m/s. If the force acting on the body is \((2\hat i+3\hat j+3\hat k)\) N, then the momentum of the body is changing in:
1. \(X\)-direction only
2. \(X\text-Y\) directions
3. \(Y\text-Z\) directions
4. In all \(X\text-Y\text-Z\) directions
A block is placed on a rough horizontal plane. A time dependent horizontal force, \(F=kt,\) acts on the block. The acceleration time graph of the block is :
| 1. | 2. | ||
| 3. | 4. |
The angle between the position vector and the acceleration vector of a particle in a non-uniform circular motion (centre of the circle is taken as the origin) will be:
1. \(0^\circ\)
2. \(45^\circ\)
3. \(75^\circ\)
4. \(135^\circ\)