A thin wire has a length of \(21.7~\text{cm}\) and a radius of \(0.46~\text{mm}\). The volume of the wire to correct significant figures is:
1. | \( 0.15~ \text{cm}^3 \) | 2. | \( 0.1443~ \text{cm}^3 \) |
3. | \( 0.14~ \text{cm}^3 \) | 4. | \( 0.144 ~\text{cm}^3\) |
1. | \(1\%\) | 2. | \(2\%\) |
3. | \(3\%\) | 4. | \(4\%\) |
The determination of the value of acceleration due to gravity \((g)\) by simple pendulum method employs the formula,
\(g=4\pi^2\frac{L}{T^2}\)
The expression for the relative error in the value of \(g\) is:
1. \(\frac{\Delta g}{g}=\frac{\Delta L}{L}+2\Big(\frac{\Delta T}{T}\Big)\)
2. \(\frac{\Delta g}{g}=4\pi^2\Big[\frac{\Delta L}{L}-2\frac{\Delta T}{T}\Big]\)
3. \(\frac{\Delta g}{g}=4\pi^2\Big[\frac{\Delta L}{L}+2\frac{\Delta T}{T}\Big]\)
4. \(\frac{\Delta g}{g}=\frac{\Delta L}{L}-2\Big(\frac{\Delta T}{T}\Big)\)
A wire of length cm and radius cm and mass gm. The maximum percentage error in density is :
(1) 4
(2) 2
(3) 1
(4) 6.8
38. A physical quantity X is related to four measurable quantities a, b, c, and d as follows . The percentage error in measuring a, b, c, and d is 1%, 2%, 3%, and 4%, respectively. What is the percentage error in quantity X?
(1) 22.1 %
(2) 13.2 %
(3) 34.6 %
(4) 23.5 %
This objective question is based on NCERT Exemplar subjective Question.
A wire has a mass of \((0.3\pm0.003)\) grams, a radius of \((0.5\pm 0.005)\) mm, and a length of \((0.6\pm0.006)\) cm. The maximum percentage error in the measurement of its density will be:
1. \(1\)
2. \(2\)
3. \(3\)
4. \(4\)
1. | \(2340.32~\text{g}\), \(0.002~\text{g}\) |
2. | \(2.340~\text{kg}\), \(0.02~\text{g}\) |
3. | \(2.3~\text{kg}\), \(0~\text{g}\) |
4. | \(2.334032~\text{kg}\), \(0.02~\text{g}\) |
A student performs an experiment for determination of where l 1 m and he commits an error of . For T, he takes the time of n oscillations with the stop watch of least count . For which of the following data, the measurement of g will be most accurate:-
n
a. 5 mm 0.2 s 10
b. 5 mm 0.2 s 20
c. 5 mm 0.1 s 20
d. 5 mm 0.1 s 50
1. (a)
2. (b)
3. (c)
4. (d)
The unit of percentage error is
1. Same as that of physical quantity
2. Different from that of physical quantity
3. Percentage error is unit less
4. Errors have got their own units which are different from that of physical quantity measured
The sum of the numbers \(436.32,227.2,\) and \(0.301\) in the appropriate significant figures is:
1. | \( 663.821 \) | 2. | \( 664 \) |
3. | \( 663.8 \) | 4. | \(663.82\) |
The mean length of an object is 5 cm. which of the following measurements is most accurate?
(1) 4.9 cm
(2) 4.805 cm
(3) 5.25 cm
(4) 5.4 cm
Two clocks are being tested against a standard clock located in a national laboratory. At 12:00:00 noon by the standard clock, the readings of the two clocks are:
Days | Clock 1 | Clock 2 |
Monday | 12:00:05 | 10:15:06 |
Tuesday | 12:01:15 | 10:14:59 |
Wednesday | 11:59:08 | 10:15:18 |
Thursday | 12:01:50 | 10:15:07 |
Friday | 11:59:15 | 10:14:53 |
Saturday | 12:01:30 | 10:15:24 |
Sunday | 12:01:19 | 10:15:11 |
If you are doing an experiment that requires precision time interval measurements, which of the two clocks will you prefer?
1. | clock 1 |
2. | clock 2 |
3. | neither clock 1 nor clock 2 |
4. | both clock 1 and clock 2 |
The period of oscillation of a simple pendulum \(T=2\pi\sqrt{\frac{L}{g}}\). Measured value of '\(L\)' is \(1.0\) m from meter scale having a minimum division of \(1\) mm and time of one complete oscillation is \(1.95\) s measured from stopwatch of \(0.01\) s resolution. The percentage error in the determination of '\(g\)' will be :
1. \(1.13\%\)
2. \(1.03\%\)
3. \(1.33\%\)
4. \(1.30\%\)
The resistance R = where V= 100 ± 5 volts and i = 10 ± 0.2 amperes. What is the total error in R
1. 5%
2. 7%
3. 5.2%
4. %
In the vernier calipers, 9 main scale divisions matched with 10 vernier scale divisions. Assume the edge of vernier scale as the '0' for Vernier Scale.The thickness of the object using the defected vernier capllipers will be:
(A) 13.3 mm
(B) 13.4 mm
(C) 13.5 mm
(D) 13.6 mm
1. | eliminating the error. |
2. | taking more number of observations. |
3. | improving least count of the instrument. |
4. | none of these. |
35. Time for 20 oscillations of a pendulum is measured as ; and . What is the accuracy of the measurement?
This objective question is based on NCERT Exemplar subjective Question.
1. | Random errors | 2. | Instrumental errors |
3. | Personal errors | 4. | Least count errors |
What is the number of significant figures in \(0.310\times 10^{3}?\)
1. | \(2\) | 2. | \(3\) |
3. | \(4\) | 4. | \(6\) |
The number of significant figures in 12500.40 is
1. 4
2. 5
3. 6
4. 7
The period of oscillation of a simple pendulum is . Measured value of L is 20.0 cm known to 1 mm accuracy and time for 100 oscillations of the pendulum is found to be 90 s using a wrist watch of 1 s resolution. The percentage error in g is:
1.
2.
3.
4.
The decimal equivalent of 1/20 upto three significant figure is
(1) 0.0500
(2) 0.05000
(3) 0.0050
(4)
A body of mass m = 3.513 kg is moving along the x-axis with a speed of 5.00 . The magnitude of its momentum is recorded as
(1) 17.6
(2) 17.565
(3) 17.56
(4) 17.57
Subtract \(12.589-12.4\) and give the answer to the correct significant figure:
1. | \(0.2\) | 2. | \(0.189\) |
3. | \(0.188\) | 4. | \(0.199\) |
Choose the correct statement.
1. Round off of 18.65 to 3 significant figures is 18.6.
2. Round off of 18.55 to 3 significant figures is 18.6.
3. Round off of 18.75 to 3 significant figures is 18.7.
4. Both (1) & (2)
If P=2.348 cm and Q=2.1 cm, then P - Q equals=?
1. 0.248 cm
2. 0.25 cm
3. 0.2 cm
4. 0.3 cm
The numbers \(2.745\) and \(2.735\) on rounding off to \(3\) significant figures will give respectively,
1. | \(2.75\) and \(2.74\) | 2. | \(2.74\) and \(2.73\) |
3. | \(2.75\) and \(2.73\) | 4. | \(2.74\) and \(2.74\) |
The number of significant digits in 1001, 100.1, 100.10, 0.001001 are, respectively,:
1. 4, 5, 4, 4
2. 4, 4, 5, 4
3. 4, 4, 4, 4
4. 5, 5, 4, 4
The random error in the arithmetic mean of 100 observations is x; then random error in the arithmetic mean of 400 observations would be
1. 4x
2.
3. 2x
4.
The length and breadth of a rectangular sheet are \(16.2\) cm and \(10.1\) cm, respectively. The area of the sheet in appropriate significant figures and error would be, respectively,
1. | \(164\pm3~\text{cm}^2\) | 2. | \(163.62\pm2.6~\text{cm}^2\) |
3. | \(163.6\pm2.6~\text{cm}^2\) | 4. | \(163.62\pm3~\text{cm}^2\) |
The following observations were taken to determine the surface tension \(T\) of water by the capillary method:
diameter of the capillary, \(D=1.25 \times 10^{-2} ~\text{m}\)
rise of water, \(h=1.45\times 10^{-2}~\text{m}\)
Using \(g= 9.80~\text{m/s}^2\) and the simplified relation, the possible error in surface tension is closest to:
1. \(0.15\%\)
2. \(1.5\%\)
3. \(2.4\%\)
4. \(10\%\)