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Highly soluble hydroxide in water is formed by -
1. Ni²⁺
2. K⁺
3. Zn²⁺
4. Al³⁺

What would you observe if excess of dilute NaOH solution is added and shaken with an aqueous solution of aluminium chloride?
1. A permanent white precipitate is formed immediately
2. No change at first but a white precipitate is formed on standing
3. A white precipitate is formed which later dissolves
4. A green precipitate which turns red on standing in air

A colourless salt gives violet colour to Bunsen flame and also turns moistured litmus paper blue. It Is:
1. Na₂CO₃
2. KNO₃
3. K₂CO₃
4. Cu(OH)₂

Which one of the following is formed on dissolving I₂ in aqueous solution of KI ?
1. KIO₄
2. KIO
3. KI₃
4. KIO₃

Hypo is chemically:
1. Na₂S₂O₃.2H₂O
2. Na₂S₂O₃.3H₂O
3. Na₂S₂O₃.4H₂O
4. Na₂S₂O₃.5H₂O

Sodium reacts with water less vigorously than potassium because:
1. it has higher atomic weight
2. it is less electropositive
3. it is more electronegative
4. it is metal

Molecular formula of Glauber's salt is :
1. MgSO₄$·$7H₂O
2. CuSO₄$·$5H₂O
3. FeSO₄$·$7H₂O
4. Na₂SO₄$·$10H₂O

An alkali metal that reacts with nitrogen to form nitride is -
1. Li
2. Na
3. Cs
4. None of the above.

Which is industrially prepared by the electrolysis of aqueous NaCl?
1. Na₂CO₃
2. NaHCO₃
3. NaOH 
4. NaOCl

Tin dissolves in boiling caustic soda solution because of the formation of soluble:
1. Sn(OH)₂
2. Sn(OH)₄
3. Na₂SnO₃
4. none of these

The pair of compounds which cannot exist together in solution is:
1. NaHCO₃ and NaOH
2. Na₂CO₃ and NaHCO₃
3. Na₂CO₃ and NaOH
4. NaHCO₃ and NaCl

Sodium burns in dry air to give:
1. Na₂O
2. Na₂O₂
3. NaO
4. Na₃N

The raw materials in Solvay process are:
1. NaOH, CaO and NH₃
2. Na₂CO₃, CaCO₃, and NH₃
3. Na₂SO₄, CaCO₃ and NH₃
4. NaCl, NH₃, CaCO₃ 

When sodium metal is dissolved in liquid ammonia, a blue solution is formed. The blue colour is due to:
1. solvated Na⁺ ions
2. solvated electrons
3. solvated ${\mathrm{NH}}_2^{-}$ions
4. solvated protons

Sodium does not form Na²⁺ ,because:
1. Sodium contains only one electron in its outermost shell
2. First ionization potential is small and the difference in first and second ionization potential is very large.
3. Radius of Na⁺² is much smaller than of Na⁺
4. None of the above.