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Arrange the following compounds in the order of
leaving group ability

1. I >II>III>IV
2. IV>III>I>II
3. III>II>I>IV
4. II>III>IV>I

On warming with I₂ and aqueous NaOH, iodoform
and sodium succinate are formed. The formula of
the compound should be
1. CH₃COCH₂CH₂CH₃
2. CH₃COC₆H₅
3. CH₃COCH₂CH₂COCH₃
4. none of these

An organic compound (A) (MF C₄H₁₀O) upon
dehydrogenation gives a compound (B) which forms
phenyl hydrazone with phenylhydrazine and both the
compounds (A) and (B) respond to iodoform test.
Hence, the compound (A) is

Identify ‘Y’ in
$\underset{\mathrm{oxidation}}{\overset{\mathrm{vigorous}}{\to }}X\underset{\mathrm{heating}}{\overset{\mathrm{Dry}}{\to }}$

In a Cannizzaro’s reaction, the intermediate that will
be the best hydride donor is

The appropriate reagent for the transformation is

1. Zn (Hg)/HCl
2. NH₂–NH₂/OH^–
3. Both 1. and 2.
4. None of the above

In the reaction
${\mathrm{CH}}_3-\mathrm{CH}=\mathrm{CH}-\mathrm{CHO}\underset{\mathrm{agent}}{\overset{\mathrm{oxidizing} }{\to }}$
${\mathrm{CH}}_3-\mathrm{CH}=\mathrm{CH}-\mathrm{COOH}$
the oxidizing agent can be
1. alkaline KMnO₄
2. acidified K₂Cr₂O₇
3. benedict’s solution
4. All of the above

When propanoic acid is treated with aqueous sodium
bicarbonate, CO₂ is liberated. The ‘C’ of CO₂
comes from
1. carboxylic acid group
2. methylene group
3. bicarbonate
4. methyl group

When glycerol is reacted with oxalic acid at 260^oC,
then the final product formed is
1. Formic acid
2. Allyl alcohol
3. Acrolein
4. Acetic Acid

Which carboxylic acid is least reactive towards
decarboxylation on heating?

The end product of the following reaction would be
$\underset{\left(\mathrm{ii}\right) ∆}{\overset{\left(\mathrm{i}\right) {\mathrm{H}}_3{\mathrm{O}}^{+}}{\to }}$

I.    R₁ = H             II R₁ = CH₃
      R₂ = CH₃             R₂ = -CH(CH₃)₂
III. R₁ = CH₃          IV R₁ = CH₃
      R₂ = CH₃              R₂ = C₂H₅
The rate of addition follows the order
1. I > II > III > IV
2. I > III > IV > II
3. I > III > II > IV
4. I > II > IV > III

The correct order of increasing reactivity towards
acid hydrolysis is
$\underset{\left(1\right)}{{\mathrm{CH}}_3{\mathrm{COOC}}_2{\mathrm{H}}_5} \underset{\left(2\right)}{C{H}_{3}COCl } \underset{\left(3\right)}{C{H}_{3}CONHC{H}_3}$
1. 1 < 2 < 3
2. 3 < 1 < 2
3. 1 < 3 < 2
4. 2 < 1 < 3

$\underset{\left(2\right){\mathrm{Br}}_2/\mathrm{KOD}}{\overset{\left(1\right){\mathrm{NH}}_3,∆}{\to }}A,\left(Major\right)$
The product ‘A’ is

$\stackrel{\mathrm{dilute} {\mathrm{OH}}^{-}}{\to }?$
The major product formed would be