Question 356 of 512

The arrangement of decreasing order of stability of H3,H5,(CH3)2H and (CH3)3  free radicals is:

(a) H3H5 > (CH3)2H > (CH3)3

(b)  (CH3)3  > (CH3)2H > H5H3

(c) H5H3 > (CH3)2H > (CH3)3  

(d) (CH3)3  > (CH3)2H >  H3>H5