In the given circuit, the potential of the point E is
(1) Zero
(2) –8 V
(3) –4/3 V
(4) 4/3 V
If a resistance R2 is connected in parallel with the resistance R in the circuit shown, then possible value of current through R and the possible value of R2 will be
(1)
(2)
(3)
(4)
A battery of e.m.f. 10 V is connected to resistance as shown in the figure below. The potential difference between the points A and B is:
1. –2 V
2. 2 V
3. 5 V
4.
A battery of emf 10 V and internal resistance 3 Ω is connected to a resistor as shown in the figure. If the current in the circuit is 0.5 A. then the resistance of the resistor will be
(1) 19 Ω
(2) 17 Ω
(3) 10 Ω
(4) 12 Ω
In the circuit shown below, The reading of the voltmeter V is
(1) 12 V
(2) 8 V
(3) 20 V
(4) 16 V
In circuit shown below, the resistances are given in ohms and the battery is assumed ideal with emf equal to 3 volt. The voltage across the resistance R4 is:
1. 0.4 V
2. 0.6 V
3. 1.2 V
4. 1.5 V
In the circuit shown, A and V are ideal ammeter and voltmeter respectively. Reading of the voltmeter will be
(1) 2 V
(2) 1 V
(3) 0.5 V
(4) Zero
The internal resistances of the two cells shown are 0.1 Ω and 0.3 Ω. If R = 0.2 Ω, the potential difference across the cell :
(1) B will be zero
(2) A will be zero
(3) A and B will be 2V
(4) A will be > 2V and B will be < 2V
Consider the circuit shown in the figure below. The current I3 is equal to:
1. 5 A
2. 3 A
3. –3 A
4. –5/6 A
If in the given figure, then resistance X will be:
1. 5 Ω
2. 10 Ω
3. 15 Ω
4. 20 Ω