Electric field is given by E =100x2 . Find the potential difference between x= 10 and x= 20 m. [This question includes concepts from 12th syllabus]

1. 5 V

2. 10 V

3. 15 V

4. 20 V

Subtopic:  Relation between Field & Potential |
 63%
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Mathematical Tools questions are over , now starting Electrostatic Potential and Capacitance questions

The figure shows some of the equipotential surfaces. Magnitude and direction of the electric field is given by

              

1.  200 V/m, making an angle 1200 with the x-axis

2. 100 V/m, pointing towards the negative x-axis

3. 200 V/m, making an angle -600 with the x-axis

4. 100 V/m, making an angle 300 with the x-axis

Subtopic:  Relation between Field & Potential |
 58%
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The electric potential V at any point O (x, y, z all in metres) in space is given by V=4x2volt. The electric field at the point (1m,0,2m) in volt/metre is -

(1) 8 along negative x-axis

(2) 8 along positive x-axis

(3) 16 along negative x-axis

(4) 16 along positive z-axis

Subtopic:  Relation between Field & Potential |
 73%
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Electric potential at any point is V=5x+3y+15z, then the magnitude of the electric field is

(1) 32

(2) 42

(3) 52

(4) 7

Subtopic:  Relation between Field & Potential |
 74%
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If potential (in volts) in a region is expressed as V(x,y,z)=6xy-y+2yz, the electric field (in N/C) at point (1,1,0) is       


(1)-(3i^+5j^+3k^)

(2)-(6i^+5j^+2k^)

(3)-(2i^+3j^+k^)

(4)-(6i^+9j^+k^

Subtopic:  Relation between Field & Potential |
 83%
NEET - 2015
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In a region, the potential is represented by V(x,y,z)=6x-8xy-8y+6yz, where V is in volts and x,y,z are in meters. The electric force experienced by a charge of 2 coulomb situated at point (1,1,1) is

(1)6√5N

(2)30N

(3)24N

(4)4√35N

Subtopic:  Relation between Field & Potential |
 66%
NEET - 2014
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\(\mathrm{A}\), \(\mathrm{B}\) and \(\mathrm{C}\) are three points in a uniform electric field. The electric potential is:

1. maximum at \(\mathrm{A}\)
2. maximum at \(\mathrm{B}\)
3. maximum at \(\mathrm{C}\)
4. same at all the three points \(\mathrm{A},\mathrm{B} ~\text{and}~\mathrm{C}\)
Subtopic:  Relation between Field & Potential |
 83%
From NCERT
NEET - 2013
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The electric potential at a point (x,y,z) is given by 

            V=-x2y-xz3+4

The electric field E at that point is 

(a) E=i^2 xy+z3+j^x2+k^3xz2

(b) E=i^2xy+j^x2+y2+k^3xz-y2

(c) E=i^z3+j^xyz+k^z2

(d) E=i^2xy-z3+j^xy2+k^3z2x

Subtopic:  Relation between Field & Potential |
 78%
NEET - 2009
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The mean free path of electrons in a metal is 4×10-8m.The electric field which can give on an average 2 eV energy to an electron in the metal will be in a unit of Vm-1 :

(1) 8×107                             

(2) 5×10-11

(3) 8×10-11                         

(4) 5×107

Subtopic:  Relation between Field & Potential |
From NCERT
NEET - 2009
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A non-conducting ring of radius 0.5 m carries a total charge of 1.11 × 10–10 C distributed non-uniformly on its circumference producing an electric field E everywhere in space. The value of the line integral l=l=0E.dl(l=0 being centre of the ring) in volt is 

(1) + 2

(2) – 1

(3) – 2

(4) Zero

Subtopic:  Relation between Field & Potential |
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