A convex lens is dipped in a liquid whose refractive index is equal to the refractive index of the lens. Then its focal length will:

The focal length of a glass $\left(\mu =1.5\right)$ lens in air is 20 cm. If it is dipped in water $\left(\mu =\frac{4}{3}\right)$, its focal length in water will be:

A plane-convex lens fits exactly into a plano-concave lens. Their plane surfaces are parallel to each other. If lenses are made of different materials of refractive indices μ₁ and μ₂ and R is the radius of curvature of the curved surface of the lenses, then the focal length of the combination is:
1. R/2(μ_{1 +} μ₂)
2. R/2(μ_{1 -} μ₂)
3. R/(μ_{1 -} μ₂)
4. 2R/(μ₂ - μ₁)

A plane convex lens (µ = 1.5) has a radius of curvature \(10~\mathrm{cm}\). It is silvered on its plane surface. The focal length of the lens after silvering is:

1. 10 cm

2. 20 cm

3. 15 cm

4. 25 cm

Two identical equiconvex thin lenses each of focal lengths 20 cm, made of material of refractive index 1.5 are placed coaxially in contact as shown. Now, the space between them is filled with a liquid with a refractive index of 1.5. The equivalent power of this arrangement will be: