For the angle of minimum deviation of a prism to be equal to its refracting angle, the prism must be made of a material whose refractive index:

1. lies between\(\sqrt{2} \text { and } 1 \text {. }\)
2. lies between 2 and \(\sqrt{2} \)
3. is less than 1.
4. is greater than 2.


 

Subtopic:  Prisms |
 64%
From NCERT
NEET - 2012
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A converging beam of rays is incident on a diverging lens. Having passed through the lens the rays intersect at a point \(15~\mathrm{cm}\) from the lens on the opposite side. If the lens is removed the point where the rays meet will move 5 cm closer to the lens. The focal length of the lens is:

1. -10 cm 2. 20 cm
3. -30 cm 4. 5 cm
Subtopic:  Lenses |
 65%
From NCERT
NEET - 2011
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The speed of light in media M1 and M2 is 1.5×108 m/s and 2.0×108 m/s respectively. A ray of light enters from medium M1 to M2 at an incidence angle i. If the ray suffers total internal reflection, the value of i is:

1. equal to \(\sin ^{-1}\left(\frac{2}{3}\right)\)
2. equal to or less than \(\sin ^{-1}\left(\frac{3}{5}\right)\) 
3. equal to or greater than \(\sin ^{-1}\left(\frac{3}{4}\right)\)
4. less than \(\sin ^{-1}\left(\frac{2}{3}\right)\)
Subtopic:  Total Internal Reflection |
 88%
From NCERT
NEET - 2010
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A boy is trying to start a fire by focusing sunlight on a piece of paper using an equiconvex lens of focal length 10 cm. The diameter of the sun is \(1.39\times 10^9~\text{m}\) and its mean distance from the earth is 1.5×1011 m. What is the diameter of the sun's image on the paper?
1. \( 9.2 \times 10^{-4} \mathrm{~m} \)
2. \(6.5 \times 10^{-4} \mathrm{~m} \)
3. \(6.5 \times 10^{-5} \mathrm{~m} \)
4. \( 12.4 \times 10^{-4} \mathrm{~m}\)

Subtopic:  Lenses |
 58%
From NCERT
NEET - 2008
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Two convex lenses of focal lengths 10 cm and 30 cm are kept at a separation of 20 cm. Then the correct statement is:

1. The effective focal length is 15 cm.
2. Chromatic aberration is minimized.
3. Combination behaves like a convergent lens.
4. All of these.


 

Subtopic:  Lenses |
 82%
From NCERT
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A microscope has an objective of focal length 1.5 cm and an eye–piece of focal length 2.5 cm. If the distance between objective and eye-piece is 25 cm, what is the approximate value of magnification produced for relaxed eye?

1. 75 2. 110
3. 140 4. 25
Subtopic:  Simple & Compound Microscope |
 63%
From NCERT
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In an astronomical telescope in normal adjustment a straight black line of length \(L\) is drawn on inside part of the objective lens. The eye-piece forms a real image of this line. The length of this image is \(l\). The magnification of the telescope is:
1. \(\frac{L}{l+1}\)
2. \(\frac{L}{l-1}\)
3. \(\frac{L+1}{L-1}\)
4. \(\frac{L}{l}\)

Subtopic:  Telescope |
 60%
From NCERT
NEET - 2015
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A person can see clearly objects only when they lie between 50 cm and 400 cm from his eyes. In order to increase the maximum distance of distinct vision to infinity, the type and power of the correcting lens, the person has to use will be:

1. Convex, +2.25 D
2. Concave, - 0.25 D
3. Concave, - 0.2 D
4. Convex, + 0.15 D

Subtopic:  Human Eye |
 76%
From NCERT
NEET - 2016
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A medium shows relation between i and r as shown. If the speed of light in the medium is nc then the value of n is:

                  

1. 1.5

2. 2

3. 2–1

4. 3–1/2

Subtopic:  Refraction at Plane Surface |
 76%
From NCERT
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The focal length of the objective lens and the eye lens is 4 mm and 25 mm respectively in a compound microscope. The distance between objective and eyepiece lens is 16 cm. Find its magnifying power for relaxed eye position:

1. 32.75   
2. 327.5 
3. 0.3275 
4. None of the above

Subtopic:  Simple & Compound Microscope |
 60%
From NCERT
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