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Q. No.A standard filament lamp consumes \(100~\text W\) when connected to \(200~\text V\) AC mains supply. The peak current through the bulb will be:
1. \(0.707~\text A\)
2. \(1~\text A\)
3. \(1.414~\text A\)
4. \(2~\text A\)
Subtopic: Â RMS & Average Values |
 74%
Level 2: 60%+
NEET - 2022
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Given below are two statements:
| Statement I: | In an AC circuit, the current through a capacitor leads the voltage across it. |
| Statement II: | In AC circuits containing pure capacitance only, the phase difference between the current and the voltage is \(\pi.\) |
| 1. | Both Statement I and Statement II are correct. |
| 2. | Both Statement I and Statement II are incorrect. |
| 3. | Statement I is correct but Statement II is incorrect. |
| 4. | Statement I is incorrect but Statement II is correct. |
Subtopic: Â Different Types of AC Circuits |
 72%
Level 2: 60%+
NEET - 2022
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Two circuits: \((1)\) an \(L\text-R\) circuit and \((2)\) an \(R\text-C\) circuit are driven by the same alternating current. The phase difference between the current and the voltage is twice in the \(1\)st case with respect to the \(2\)nd case and both the angles add up to \(90^\circ.\) The resistances are equal in both cases. The ratio of their reactances (first: second) is:
| 1. | \(\sqrt3:1\) | 2. | \(1:\sqrt3\) |
| 3. | \(3:1\) | 4. | \(2:1\) |
Subtopic: Â Different Types of AC Circuits |
 53%
Level 3: 35%-60%
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The primary coil of a transformer, when connected to a \(10~\text{V}\text-\)DC battery, draws a current of \(1~\text{mA}.\) The number of turns in the primary and secondary coils are \(50\) and \(100,\) respectively. The voltage across the secondary coil and the current drawn by the circuit in the secondary are respectively:
| 1. | \(20~\text{V}\) and \(2.0~\text{mA}\) |
| 2. | \(10~\text{V}\) and \(0.5~\text{mA}\) |
| 3. | zero and therefore no current |
| 4. | \(20~\text{V}\) and \(0.5~\text{mA}\) |
Subtopic: Â Transformer |
Level 3: 35%-60%
NEET - 2013
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An alternating emf (AC) is applied across the circuit shown in the figure. Let \(V_{AX}\) be the voltage across the inductor \(L,\) and \(V_{XY}\) be the voltage across the resistor \(R.\) Let the angular frequency be \(\omega.\) The phase difference between \(V_{XY}\) and \(V_{AX}\):
| 1. | depends on the ratio \(\dfrac{\omega L}{R}\) |
| 2. | depends on the quantity \(\sqrt{(\omega L)^2+R^2}\) |
| 3. | depends on \(L\) and \(R,\) but not on \(\omega\) |
| 4. | is independent of \(L,R,\omega\) |
Subtopic: Â Different Types of AC Circuits |
Level 3: 35%-60%
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A household ac circuit has an applied voltage of \(220\) V (RMS) and the current flowing through the circuit is \(2.2\) A (RMS), the phase difference between them being \(60^\circ.\) Then:
| 1. | the impedance in the circuit is \(100~\Omega.\) |
| 2. | the resistance in the circuit is \(200~\Omega.\) |
| 3. | the power dissipated is \(484\) W. |
| 4. | all the above are true. |
Subtopic: Â Different Types of AC Circuits |
 64%
Level 2: 60%+
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An AC source given by \(V=V_m\sin(\omega t)\) is connected to a pure inductor \(L\) in a circuit and \(I_m\) is the peak value of the AC current. The instantaneous power supplied to the inductor is:
| 1. | \(\dfrac{V_mI_m}{2}\mathrm{sin}(2\omega t)\) | 2. | \(-\dfrac{V_mI_m}{2}\mathrm{sin}(2\omega t)\) |
| 3. | \({V_mI_m}\mathrm{sin}^{2}(\omega t)\) | 4. | \(-{V_mI_m}\mathrm{sin}^{2}(\omega t)\) |
Subtopic: Â Power factor |
Level 3: 35%-60%
NEET - 2022
Hints
A series \(LCR\) circuit with inductance \(10~\text{H}\), capacitance \(10~\mu \text{F}\), resistance \(50~\Omega\) is connected to an AC source of voltage, \(V=200 \sin (100 t) \text { volt }\). If the resonant frequency of the \(LCR\) circuit is \(\nu_0\) and the frequency of the AC source is \(\nu\), then:
| 1. | \(\nu=100 ~\text{Hz} ; ~\nu_0=\dfrac{100}{\pi} ~\text{Hz}\) |
| 2. | \(\nu_0=\nu=50~\text{Hz}\) |
| 3. | \(\nu_0=\nu=\dfrac{50}{\pi} ~\text{Hz}\) |
| 4. | \(\nu_{0}=\dfrac{50}{\pi}~ \text{Hz}, \nu=50 ~\text{Hz}\) |
Subtopic: Â Different Types of AC Circuits |
 74%
Level 2: 60%+
NEET - 2022
Hints
The peak voltage of the AC source is equal to:
| 1. | \(1 / \sqrt{2}\) times the rms value of the AC source. |
| 2. | the value of voltage supplied to the circuit. |
| 3. | the rms value of the AC source. |
| 4. | \(\sqrt{2}\) times the rms value of the AC source. |
Subtopic: Â RMS & Average Values |
 78%
Level 2: 60%+
NEET - 2022
Hints
The primary has \(100\) turns with \(100\) V RMS applied to it while the secondary has a total number of \(20\) turns, with the connection \(C\) made at the centre. The current \(i\) flowing towards \(C\) has the (RMS) value:
| 1. | \(2\) A | 2. | \(2\sqrt2\) A |
| 3. | \(\sqrt2\) A | 4. | zero |
Subtopic: Â Transformer |
 54%
Level 3: 35%-60%
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