At point A on the earth's surface, the angle of dip is, $\delta =+25°$. At a point B on the earth's surface, the angle of dip is, $\delta =-25°$. We can interpret that:

1. A and B are both located in the southern hemisphere.

2. A and B are both located in the northern hemisphere.

3. A is located in the southern hemisphere and B is located in the northern hemisphere.

4. A is located in the northern hemisphere and B is located in the southern hemisphere.

Subtopic:  Earth's Magnetism |
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The relation amongst the three elements of Earth's magnetic field, namely horizontal component H, vertical component V and dip angle is: (${B}_{E}$=total magnetic field)

1. V=${B}_{E}$tan$\delta$, H=${B}_{E}$

2. V=${B}_{E}$sin$\delta$, H=${B}_{E}$cos$\delta$

3. V=${B}_{E}$cos$\delta$, H=${B}_{E}$sin $\delta$

4. V=${B}_{E}$, H=${B}_{E}$tan$\delta$

Subtopic:  Earth's Magnetism |
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If  and ${\theta }_{2}$ are the apparent angles of dip observed in two vertical planes at right angles to each other, then the true angle of dip $\theta$ is given by:
1. ${\mathrm{tan}}^{2}\theta ={\mathrm{tan}}^{2}{\theta }_{1}+ta{n}^{2}{\theta }_{2}$
2. $co{t}^{2}\theta =co{t}^{2}{\theta }_{1}-co{t}^{2}{\theta }_{2}$
3. ${\mathrm{tan}}^{2}\theta ={\mathrm{tan}}^{2}{\theta }_{1}+ta{n}^{2}{\theta }_{2}$
4. $co{t}^{2}\theta =co{t}^{2}{\theta }_{1}+co{t}^{2}{\theta }_{2}$

Subtopic:  Earth's Magnetism |
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A compass needle which is allowed to move in a horizontal plane is taken to a geomagnetic pole. It

1. will become rigid showing no movement

2. will stay in any position

3. will stay in north-south direction only

4. will stay in east-west direction only

Subtopic:  Earth's Magnetism |
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