- 1(current)
Q. No.A conducting wire is bent into the form of a square \(ABCD,\) and electrical connections are established in two different ways:
The same potential difference is established between the two connected ends. Current is, however, allowed to take only a single path from the positive to the negative terminal by disconnecting the other path. Let the magnetic field at the centre in these cases be \(B_\text I,B_\text{II}.\) Then, \(\frac{B_\text I}{B_\text{II}}=\)
| (I) | at two adjacent vertices \(A,B\) |
| (II) | at two points \(A,C\) at the ends of a diagonal. |
| 1. | \(2\) | 2. | \(\dfrac12\) |
| 3. | \(\dfrac{1}{\sqrt2}\) | 4. | \(1\) |
Subtopic: Â Magnetic Field due to various cases |
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A long current-carrying solenoid produces a magnetic field \(B\) at its centre, \(O\). When a current-carrying wire is placed parallel to the axis of the solenoid, the field at \(O\) has the magnitude \(2B\). The field due to wire has the magnitude (at \(O\)) of:
| 1. | \(B\) | 2. | \(3B\) |
| 3. | \(\dfrac {B} {\sqrt3}\) | 4. | \(\sqrt 3~ B\) |
Subtopic: Â Magnetic Field due to various cases |
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From NCERT
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The variation of the magnetic field along the axis of a solenoid is graphically represented by:
(\(O\) is the centre with \(I,I'\) as the extremities of the solenoid along the axis)
| 1. |  |
2. |  |
| 3. |  |
4. |  |
Subtopic: Â Magnetic Field due to various cases |
 57%
From NCERT
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