A wire of length \(L\) meters carrying a current of \(I\) amp is bent in the form of a circle. What is its magnetic moment?
1. \( \frac{{IL}^2}{4} ~\text{A}\text-\text{m}^2 \)
2. \( \frac{{I} \times \pi {L}^2}{4} ~\text{A}\text-\text{m}^2 \)
3. \( \frac{2 {IL}^2}{\pi}~\text{A}\text-\text{m}^2 \)
4. \( \frac{{IL}^2}{4 \pi}~\text{A}\text-\text{m}^2 \)

Subtopic:  Magnetic Moment |
 74%
From NCERT
NEET - 2020
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A proton carrying \(1~\text{MeV}\) kinetic energy is moving in a circular path of radius \(R\) in a uniform magnetic field. What should be the energy of an \(\alpha \text- \)particle to describe a circle of the same radius in the same field?
1. \(1~\text{MeV}\)
2. \(0.5~\text{MeV}\)
3. \(4~\text{MeV}\)
4. \(2~\text{MeV}\)

Subtopic:  Lorentz Force |
 80%
From NCERT
AIPMT - 2012
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A galvanometer of resistance, \(\mathrm G,\) is shunted by the resistance of \(\mathrm S\) ohm. How much resistance is to be put in series with the galvanometer to keep the main current in the circuit unchanged?

1. \( \mathrm{G \over (S+G)}\) 2. \( \mathrm{S^2 \over (S+G)}\)
3. \( \mathrm{SG \over (S+G)}\) 4. \( \mathrm{G^2 \over (S+G)}\)
Subtopic:  Conversion to Ammeter & Voltmeter |
From NCERT
AIPMT - 2011
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Charge q is uniformly spread on a thin ring of radius R. The ring rotates about its axis with a uniform frequency of f Hz. The magnitude of magnetic induction at the centre of the ring is:

1. μ0qf2πR

2. μ0qf2R

3. μ0q2fR

4. μ0q2πfR

Subtopic:  Magnetic Field due to various cases |
 83%
From NCERT
AIPMT - 2011
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A square loop, carrying a steady current I, is placed in a horizontal plane near a long straight conductor carrying a steady current I1 at a distance d from the conductor as shown in the figure. The loop will experience:

  
 

1. a net attractive force towards the conductor
2. a net repulsive force away from the conductor
3. a net torque acting upward perpendicular to the horizontal plane
4. a net torque acting downward normal to the horizontal plane
Subtopic:  Current Carrying Loop: Force & Torque |
 84%
From NCERT
AIPMT - 2011
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A current loop consists of two identical semicircular parts each of radius R, one lying in the x-y plane and the other in x-z plane. If the current in the loop is I, then the resultant magnetic field due to the two semicircular parts at their common centre is:

1. μ0i2R

2. μ0i4R

3. μ0i2R

4. μ0i22R

Subtopic:  Magnetic Field due to various cases |
 66%
From NCERT
AIPMT - 2010
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A closely wound solenoid of 2000 turns and an area of cross-section of 1.5 × 10–4 m2 carries a current of 2.0 A. It is suspended through its centre and perpendicular to its length, allowing it to turn in a horizontal plane in a uniform magnetic field of 5 × 10–2 Tesla, making an angle of 30o with the axis of the solenoid. What will be the torque on the solenoid?

1. 1.5 × 10–3 Nm

2. 1.5 × 10–2 Nm

3. 3 × 10–2 Nm

4. 3 × 10–3 Nm

Subtopic:  Current Carrying Loop: Force & Torque |
 78%
From NCERT
AIPMT - 2010
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A particle having a mass of \(10^{-2}\) kg carries a charge of \(5\times 10^{-8}~\mathrm{C}\). The particle is given an initial horizontal velocity of \(10^5~\mathrm{ms^{-1}}\) in the presence of electric field \(\vec{E}\) and magnetic field \(\vec{B}\) . To keep the particle moving in a horizontal direction, it is necessary that:
 

(a) \(\vec{B}\) should be perpendicular to the direction of velocity and \(\vec{E}\)
should be along the direction of velocity.
(b) Both \(\vec{B}\) and \(\vec{E}\) should be along the direction of velocity.
(c) Both \(\vec{B}\) and \(\vec{E}\) are mutually perpendicular and perpendicular to the direction of velocity
(d) \(\vec{B}\) should be along the direction of velocity and \(\vec{E}\) should be perpendicular to the direction of velocity.
 

Which one of the following pairs of statements is possible?

1. (c) and (d)
2. (b) and (c)
3. (b) and (d)
4. (a) and (c)
Subtopic:  Lorentz Force |
 62%
From NCERT
AIPMT - 2010
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A coil of one loop is made from a wire of length L and thereafter a coil of two loops is made from same wire. The ratio of magnetic field at the centre of the coils will be:
1.  1 : 4
2.  1 : 1
3.  1 : 8
4.  4 : 1

Subtopic:  Magnetic Field due to various cases |
 76%
From NCERT
AIPMT - 1998
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For the adjoining figure, the magnetic field at a point 'P' will be:

1. μ04π

2. μ0π

3. μ02π

4. μ02π

Subtopic:  Magnetic Field due to various cases |
 77%
From NCERT
AIPMT - 2000
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