The horizontal component of the earth’s magnetic field at a certain place is \(3.0\times10^{-5}~\text{T}\) and the direction of the field is from the geographic south to the geographic north. A very long straight conductor is carrying a steady current of \(1~\text{A}\). What is the force per unit length on it when it is placed on a horizontal table and the direction of the current east to west?
1. \(3\times10^{-5}~\text{N m}^{-1}\)
2. \(2\times10^{-7}~\text{N m}^{-1}\)
3. zero
4. \(5\times10^{-7}~\text{N m}^{-1}\)

Subtopic:  Force between Current Carrying Wires |
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NEET 2023 - Target Batch - Aryan Raj Singh
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The horizontal component of the earth’s magnetic field at a certain place is 3.0 ×10–5 T and the direction of the field is from the geographic south to the geographic north. A very long straight conductor is carrying a steady current of 1 A. What is the force per unit length on it when it is placed on a horizontal table and the direction of the current is south to north?

1. 3×10-5 N m-1
2. 2×10-7 N m-1
3. 0
4. 5×10-7 N m-1

Subtopic:  Force between Current Carrying Wires |
 70%
To view explanation, please take trial in the course.
NEET 2023 - Target Batch - Aryan Raj Singh
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Links