- 1(current)
Q. No.A long wire carrying a steady current is bent into a circular loop of one turn. The magnetic field at the centre of the loop is \(B\). It is then bent into a circular coil of \(n\) turns. The magnetic field at the centre of this coil of \(n\) turns will be:
1. \(nB\)
2. \(n^2B\)
3. \(2nB\)
4. \(2n^2B\)
1. \(nB\)
2. \(n^2B\)
3. \(2nB\)
4. \(2n^2B\)
Subtopic: Â Magnetic Field due to various cases |
 85%
From NCERT
NEET - 2016
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NEET 2026 - Target Batch - Vital
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- 1(current)
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