The net resistance of the circuit between \(A\) and \(B\) is:
1. | \(\dfrac{8}{3}~\Omega\) | 2. | \(\dfrac{14}{3}~\Omega\) |
3. | \(\dfrac{16}{3}~\Omega\) | 4. | \(\dfrac{22}{3}~\Omega\) |
1. | \(7R\) | 2. | \(5R\) |
3. | \(4R\) | 4. | \(3R\) |
In the circuit shown in the figure below, the current supplied by the battery is:
1. \(2~\text A\)
2. \(1~\text A\)
3. \(0.5~\text A\)
4. \(0.4~\text A\)
In a Wheatstone bridge, all four arms have equal resistance \(R.\) If the resistance of the galvanometer arm is also \(R,\) the equivalent resistance of the combination is:
1. | \(R/4\) | 2. | \(R/2\) |
3. | \(R\) | 4. | \(2R\) |
In the circuit shown in the figure below, if the potential difference between \(B\) and \(D\) is zero, then value of the unknown resistance \(X\) is:
1. | \(4~\Omega\) | 2. | \(2~\Omega\) |
3. | \(3~\Omega\) | 4. | EMF of a cell is required to find the value of \(X\) |
Three resistances \(\mathrm P\), \(\mathrm Q\), and \(\mathrm R\), each of \(2~\Omega\) and an unknown resistance \(\mathrm{S}\) form the four arms of a Wheatstone bridge circuit. When the resistance of \(6~\Omega\) is connected in parallel to \(\mathrm{S}\), the bridge gets balanced. What is the value of \(\mathrm{S}\)?
1. | \(2~\Omega\) | 2. | \(3~\Omega\) |
3. | \(6~\Omega\) | 4. | \(1~\Omega\) |
Figure \((a)\) below shows a Wheatstone bridge in which \(P,Q,R,S\) are fixed resistances, \(G\) is a galvanometer, and \(B\) is a battery. For this particular case, the galvanometer shows zero deflection. Now, only the positions of \(B\) and \(G\) are interchanged, as shown in the figure \((b).\) The new deflection of the galvanometer:
1. is to the left
2. is to the right
3. is zero
4. depends on the values of \(P,Q,R,S\)
Column-I | Column-II | ||
(A) | Equivalent resistance between \(a\) and \(b\) | (P) | \(\dfrac{R}{2}\) |
(B) | Equivalent resistance between \(a\) and \(c\) | (Q) | \(\dfrac{5R}{8}\) |
(C) | Equivalent resistance between \(b\) and \(d\) | (R) | \(R\) |
1. | (A )→ (P), (B) → (Q), (C) → (R) |
2. | (A) → (Q), (B) → (P), (C)→ (R) |
3. | (A ) → (R), (B) → (P), (C) → (Q) |
4. | (A ) → (R), (B) → (Q), (C) → (P) |
For the network shown in the figure below, the value of the current \(i\) is:
1. \(\frac{18V}{5}\)
2. \(\frac{5V}{9}\)
3. \(\frac{9V}{35}\)
4. \(\frac{5V}{18}\)