For the circuit shown in the figure, the current \(I\) will be:

 

1.	\(0.75~\text{A}\)	2.	\(1~\text{A}\)
3.	\(1.5~\text{A}\)	4.	\(0.5~\text{A}\)

Two solid conductors are made up of the same material and have the same length and the same resistance. One of them has a circular cross-section of area \(  𝐴 _1\) and the other one has a square cross-section of area \(A_2.\) The ratio of \(𝐴 _1 / 𝐴 _2  \) is:

For the circuit given below, Kirchhoff's loop rule for the loop \(BCDEB\) is given by the equation:

The equivalent resistance between \(A\) and \(B\) for the mesh shown in the figure is:

A cell having an emf \(\varepsilon\) and internal resistance \(r\) is connected across a variable external resistance \(R\). As the resistance \(R\) is increased, the plot of potential difference \(V\) across \(R\) is given by:

1.		2.
3.		4.

In the circuit shown in the figure below, if the potential at point \(A\) is taken to be zero, the potential at point \(B\) will be:

1. \(+1\) V
2. \(-1\) V
3. \(+2\) V
4. \(-2\) V

The net resistance of the circuit between \(A\) and \(B\) is:

Two batteries, one of emf \(18\) volts and internal resistance \(2~\Omega\) and the other of emf \(12\) V and internal resistance \(1~\Omega,\) are connected as shown. The voltmeter \(\mathrm{V}\) will record a reading of: 

1. \(18\) V
2. \(30\) V
3. \(14\) V
4. \(15\) V

A \(5~\text A\) fuse wire can withstand a maximum power of \(1~\text W\) in a circuit. The resistance of the fuse wire is:
1. \(5~\Omega\)
2. \(0.04~\Omega\)
3. \(0.2~\Omega\)
4. \(0.4~\Omega\)

For the network shown in the figure below, the value of the current \(i\) is:

     
1. \(\frac{18V}{5}\)
2. \(\frac{5V}{9}\)
3. \(\frac{9V}{35}\)
4. \(\frac{5V}{18}\)