When sound waves produced under water emerge into the air, then:
1. the frequency increases, and wavelength decreases.
2. the frequency remains constant, but the wavelength decreases.
3. the frequency decreases, wavelength remains constant.
4. the frequency remains constant but the wavelength increases.

Subtopic:  Speed of Sound |
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When a string vibrates in its second harmonic mode, at which point on the string is the motion maximal?
1. One-quarter of the length away from an end.
2. In the middle, between the two ends.
3. One-third of the length away from an end.
4. The amplitude is the same at any point on the string.
Subtopic:  Travelling Wave on String |
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Increasing the wave amplitude of a standing wave will:
1. increase the number of nodes.
2. increase the number of antinodes.
3. increase the displacement of the cord at a node.
4. increase the displacement of the cord at an antinode.
Subtopic:  Standing Waves |
 58%
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Suppose a string is \(20\) m long. Which of the following wavelengths is possible for standing waves on this string?
1. \(3.5\) m 2. \(13.3\) m
3. \(30\) m 4. \(80\) m
Subtopic:  Standing Waves |
From NCERT
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The addition of two waves with slightly different frequencies results in the production of beats or a beat frequency. The result can be monitored using an oscilloscope. Consider the two figures shown below:
                          
Keeping the lower frequency wave constant, we increase the frequency of the other wave. You would expect the display on the oscilloscope to go from:
1. Figure \(\mathrm I\) to Figure \(\mathrm{II}\).
2. Figure \(\mathrm{II}\) to Figure \(\mathrm{I}\).
3. There will not be a shift between Figure \(\mathrm{I}\) and Figure \(\mathrm{II}\), but the amplitude will increase.
4. There will not be a shift between Figure \(\mathrm{I}\) and Figure \(\mathrm{II}\), but the display will become brighter.
Subtopic:  Beats |
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A taut string of length \(2\) m is fixed at both ends and plucked. The speed of waves on the string is \(3\times10^4\) m/s (see figure).

If the wavelength of the fundamental frequency is \(\lambda_1,\)​ and the wavelength of the second harmonic is \(\lambda_2,\) what is the ratio \(\dfrac{\lambda_1}{\lambda_2}?\)

1. \(0.5\) 2. \(1\)
3. \(2\) 4. \(4\)
Subtopic:  Standing Waves |
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The ratio of the speed of sound in nitrogen gas to that in helium gas, at \(300\) K is:
1. \(\sqrt{\dfrac{2}{7}}\) 2. \(\sqrt{\dfrac{1}{7}}\)
3. \(\dfrac{\sqrt{3 }}{5}\) 4. \(\dfrac{\sqrt{6 }}{5}\)
Subtopic:  Speed of Sound |
From NCERT
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Given below are two statements:
 
Statement I: Sound waves travelling from air into water, incident obliquely, bend towards the normal.
Statement II: Sound waves travel more slowly in water than in air.
 
1. Statement I is incorrect and Statement II is correct.
2. Both Statement I and Statement II are correct.
3. Both Statement I and Statement II are incorrect.
4. Statement I is correct and Statement II is incorrect.
Subtopic:  Speed of Sound |
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The equation of vibration of a taut string, fixed at both ends, is given by:    \(y=(4~\text{mm})~\cos\left(\dfrac{\pi x}{30~\text{cm}}\right)~\sin\Big(400\pi s^{-1}t\Big) \)
At which points is the amplitude equal to \(2\) mm?
1. \(x = \) \(10\) cm, \(20\) cm, \(30\) cm, \(40\) cm
2. \(x=\) \(10\) cm, \(15\) cm, \(30\) cm, \(45\) cm
3. \(x =\) \(10\) cm, \(20\) cm, \(40\) cm, \(80\) cm
4. \(x = \) \(10\) cm, \(20\) cm, \(40\) cm, \(50\) cm
Subtopic:  Standing Waves |
From NCERT
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A string fixed at both ends is under tension \(T.\) It has a length \(L,\) and mass \(m.\) The fundamental frequency of the vibration is: 
1. \(\dfrac{ 1}{2L} \sqrt {\dfrac{T}{m}}\)
2. \(\dfrac{1}{4 L} \sqrt{\dfrac{T}{m}}\)
3. \(\dfrac{1}{2} \sqrt{\dfrac{TL}{2m}}\)
4. \(\dfrac{1}{2} \sqrt{\dfrac{T}{m L}}\)
Subtopic:  Travelling Wave on String |
 57%
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