In an adiabatic process, the density of a diatomic gas becomes \(32\) times its initial value. The final pressure of the gas is found to be \(n\) times the initial pressure. The value of \(n\) is:
1. \(326\)
2. \(\dfrac{1}{32}\)
3. \(32\)
4. \(128\)

Subtopic:  Types of Processes |
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A closed vessel contains \(0.1\) mole of a monatomic ideal gas at \(200\) K. If \(0.05\) mole of the same gas at \(400\) K is added to it, the final equilibrium temperature (in K) of the gas in the vessel will be closed to:
1. \(133\)
2. \(57\)
3. \(266\)
4. \(504\)

Subtopic:  Types of Processes |
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\(n\) moles of a perfect gas undergoes a cyclic process ABCA (see figure) consisting of the following processes.

\(A\rightarrow B\) Isothermal expansion at temperature \(T\) so that the volume is doubled from \(V_1\) to \(V_2=2V_1\) and pressure changes from \(P_1\) to \(P_2.\)
\(B\rightarrow C\) Isobaric compression at pressure \(P_2\) to initial volume \(V_1\).
\(C\rightarrow A\) Isochoric change leading to change of pressure from \(P_2\) to \(P_1\).

Total work done in the complete cycle \(ABCA\) is: 

  

1. \(0\)
2. \(nRT(\ln 2-\frac{1}{2})\)
3. \(nRT\ln 2\)
4. \(nRT(\ln 2+\frac{1}{2})\)

Subtopic:  Work Done by a Gas |
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Match List-I with List-II and choose the correct option:

List-I List-II
(a) Isothermal process (i) Pressure constant
(b) Isochoric process (ii) Temperature constant
(c) Adiabatic process (iii) Volume constant
(d) Isobaric process (iv) Heat content is constant
    
1. (a) → (i), (b) → (iii), (c) → (ii), (d) → (iv)
2. (a) → (ii), (b) → (iii), (c) → (iv), (d) → (i)
3. (a) → (ii), (b) → (iv), (c) → (iii), (d) → (i)
4. (a) → (iii), (b) → (ii), (c) → (i), (d) → (iv)
Subtopic:  Types of Processes |
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The thermodynamic process is shown below on a \(P-V\) diagram for one mole of an ideal gas. If \(V_2=2V_1\) then the ratio of temperature \(T_2/T_1\) is:

  
1. \(\frac{1}{2}\)
2. \(2\)
3. \(\sqrt{2}\)
4. \(\frac{1}{\sqrt{2}}\)

Subtopic:  Types of Processes |
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If one mole of an ideal gas at \((p_1,V_1)\) is allowed to expand reversibly and isothermally \((A\rightarrow B),\) its pressure is reduced to one-half of the original pressure (see figure). This is followed by a constant-volume cooling till its pressure is reduced to one-fourth of the initial value (\((B\rightarrow C).\) Then it is restored to its initial state by a reversible adiabatic compression\((C\rightarrow A).\) The net work done by the gas is:

               
1. \(RT\left(\ln 2-\dfrac{1}{2(\gamma-1)}\right) \)
2. \(-\dfrac{RT}{2(\gamma-1)} \)
3. \(0\)
4. \(RT\ln2\)

Subtopic:  Work Done by a Gas |
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A diatomic gas, having \(C_P=\dfrac{7}{2}R\) and \(C_V=\dfrac{5}{2}R\) is heated at constant pressure. The ratio of \(dU:dQ:dW\) is:
1. \(5:7:3\)
2. \(5:7:2\)
3. \(3:7:2\)
4. \(3:5:2\)

Subtopic:  Molar Specific Heat |
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In a certain thermodynamical process, the pressure of a gas depends on its volume as \(kV^3.\) The work done when the temperature changes from \(100^\circ \text{C}\) to \(300^\circ \text{C}\) will be:
(where \(n\) denotes number of moles of a gas)

1. \(20nR\) 2. \(30nR\)
3. \(40nR\) 4. \(50nR\)
Subtopic:  Work Done by a Gas |
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Match the thermodynamic processes taking place in a system with the correct conditions. In the table: \(\Delta Q\) is the heat supplied, \(\Delta W\) is the work done and \(\Delta U\) is change in internal energy of the system.

Process  Condition
(I) Adiabatic  (A) \(\Delta W=0\)
(II) Isothermal (B) \(\Delta Q=0\)
(III) Isochoric (C) \(\Delta U\neq0,\Delta W\neq0,\Delta Q\neq0\)
(IV) Isobaric (D) \(\Delta U=0\)
 
1. (I) – (B), (II) – (A), (III) – (D), (IV) – (C)
2. (I) – (A), (II) – (A), (III) – (B), (IV) – (C)
3. (I) – (A), (II) – (B), (III) – (D), (IV) – (D)
4. (I) – (B), (II) – (D), (III) – (A), (IV) – (C)
Subtopic:  Types of Processes |
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The change in the magnitude of the volume of an ideal gas when a small additional pressure \(\Delta P\) is applied at constant temperature, is the same as the change when the temperature is reduced by a small quantity \(\Delta T\) at constant pressure. The initial temperature and pressure of the gas were \(300~\text{K}\) and \(2~\text{atm}\). respectively. If \(|\Delta T|=C|\Delta P|\) then the value of \(C\) in ( K/atm) is:
1. \(50\)
2. \(100\)
3. \(150\)
4. \(200\)

Subtopic:  Types of Processes |
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