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Q. No.A monoatomic ideal gas undergoes a process given by the equation: \({\dfrac{pT}{V}}=\text{constant.}\) The molar specific heat capacity in the process equals:
| 1. | \({\dfrac{3}{2}}R\) | 2. | \({\dfrac{5}{2}}R\) |
| 3. | \({\dfrac{1}{2}}R\) | 4. | zero |
Subtopic: Â Molar Specific Heat |
From NCERT
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NEET 2026 - Target Batch - Vital
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NEET 2026 - Target Batch - Vital
A thermally insulated vessel contains an ideal gas of molecular mass \(M\) and a specific heat ratio of \(1.4.\) The vessel is moving with speed \(v\) and is suddenly brought to rest. Assuming no heat is lost to the surroundings, then the vessel temperature of the gas increases by:
(\(R=\) universal gas constant)
(\(R=\) universal gas constant)
| 1. | \(\dfrac{M v^2}{7 R} \) | 2. | \(\dfrac{M v^2}{5 R} \) |
| 3. | \(\dfrac{2M v^2}{7 R} \) | 4. | \(\dfrac{7M v^2}{5 R} \) |
Subtopic: Â Molar Specific Heat |
 56%
From NCERT
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A monoatomic gas performs a work of \(\dfrac{ Q} {4}\) where \(Q\) is the heat supplied to it. During this transformation, the molar heat capacity of the gas will be: (\(R\) is the gas constant.)
| 1. | \(R\) | 2. | \(2R\) |
| 3. | \(3R\) | 4. | \(4R\) |
Subtopic: Â Molar Specific Heat |
 59%
From NCERT
JEE
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