A spherical drop of water has a radius of 1 mm. If the surface tension of water is 70×10-3 N/m, the difference in pressures inside and outside the spherical drop is:

1. 35 N / m2 2. 70 N / m2
3. 140 N / m2 4. Zero
Subtopic:  Surface Tension |
 82%
From NCERT
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The property of surface tension of the liquid is due to:

1. the gravitational force of attraction between the molecules.
2. the cohesive forces between the molecules.
3. the adhesive force between the molecules.
4. the formation of ionic bonds between the molecules.

Subtopic:  Surface Tension |
 78%
From NCERT
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In order to float a ring of area 0.04 m2 in a liquid of surface tension 75 N/m, the required surface energy will be:

1. 3 J 2. 6.5 J
3. 1.5 J  4. 4 J
Subtopic:  Surface Tension |
 78%
From NCERT
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Small droplets of liquid are usually more spherical in shape than the larger drops of the same liquid because:

1. the force of surface tension is equal and opposite to the force of gravity.
2. the force of surface tension predominates the force of gravity.
3. the force of gravity predominates the force of surface tension.
4. the force of gravity and the force of surface tension act in the same direction and are equal.

Subtopic:  Surface Tension |
 67%
From NCERT
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If the excess pressure inside a soap bubble is balanced by an oil column of height of \(2\) mm, then the surface tension of the soap solution will be: (radius of the soap bubble, \(r=1\) cm and density of oil, \(d=0.8\) gm/cm3)
1. \(3.9\) N/m
2. 3.9×10-2 N/m
3. 3.9×10-3 N/m
4. \(3.9\) dyne/m

Subtopic:  Surface Tension |
 68%
From NCERT
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The energy needed to break a drop of radius R into n drops of radii r is given by:

1. 4πT(nr2-R2)

2. 43π(r3n-R2)

3. 4πT(R2-nr2)

4. 4πT(r2n+R2)

Subtopic:  Surface Tension |
 69%
From NCERT
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A wooden stick 2 m long is floating on the surface of the water. The surface tension of water is 0.07 N/m. By putting soap solution on one side of the stick, the surface tension is reduced to 0.06 N/m. The net force on the stick due to surface tension will be:

1. 0.07 N 2. 0.06 N
3. 0.01 N 4. 0.02 N
Subtopic:  Surface Tension |
 66%
From NCERT
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The surface tension of a liquid is \(5\) N m-1. If a film is held on a ring of area \(0.02\) m2, then its total surface energy is:
1. \(3\times\) 10-2 J
2. \(2\times\) 10-1 J
3. \(3\times\) 10-3J
4. 10-1 J

Subtopic:  Surface Tension |
 65%
From NCERT
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Two soap bubbles are connected by a tube as shown in the figure. Which of the following statement is true?
                                  

1. The volume of A will increase. 2. The volume of A will remain constant.
3. The volume of B will increase. 4. The volume of B will decrease.
Subtopic:  Surface Tension |
 68%
From NCERT
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A certain number of spherical drops of a liquid of radius r coalesce to form a single drop of radius R and volume V. If T is the surface tension of the liquid, then:\(\text { Energy }=4 V T\left(\frac{1}{r}-\frac{1}{R}\right) \text { is released } \)

1. Energy = \(4 V T\left(\frac{1}{r}-\frac{1}{R}\right)\) is released 2. Energy =\(3 V T\left(\frac{1}{r}+\frac{1}{R}\right)\)  is released
3. Energy =\(3 V T\left(\frac{1}{r}-\frac{1}{R}\right)\) is released 4. Energy is neither released nor absorbed

Subtopic:  Surface Tension |
 65%
From NCERT
NEET - 2014
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