Steel and copper wires of the same length and area are stretched by the same weight one after the other. Young's modulus of steel and copper are \(2\times10^{11} ~\text{N/m}^2\) and  \(1.2\times10^{11}~\text{N/m}^2\). The ratio of increase in length is: 

1. \(2 \over 5\) 2. \(3 \over 5\)
3. \(5 \over 4\) 4. \(5 \over 2\)
Subtopic:  Young's modulus |
 91%
From NCERT
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A steel ring of radius \(\mathrm{r}\) and cross-section area \(\mathrm{A}\) is fitted onto a wooden disc of radius \(\mathrm{R}(\mathrm{R}>\mathrm{r}).\) If Young's modulus is \(\mathrm{E},\) then the force with which the steel ring is expanded is:

1. \(\mathrm{AE} \frac{\mathrm{R}}{\mathrm{r}} \) 2. \(A E \frac{R-r}{r} \)
3. \(\frac{E}{A} \frac{R-r}{A} \) 4. \(\frac{\mathrm{Er}}{\mathrm{AR}}\)
Subtopic:  Young's modulus |
 85%
From NCERT
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If the ratio of lengths, radii and Young's modulus of steel and brass wires in the figure are \(a,\) \(b\) and \(c\) respectively, then the corresponding ratio of increase in their lengths will be:

      

1. 2a2cb

2. 3a2b2c

3. 2acb2

4. 3c2ab2

Subtopic:  Young's modulus |
 84%
From NCERT
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Two wires are made of the same material and have the same volume. The first wire has a cross-sectional area \(A\) and the second wire has a cross-sectional area \(3A\). If the length of the first wire is increased by \(\Delta l\) on applying a force \(F\), how much force is needed to stretch the second wire by the same amount?

1. \(9F\) 2. \(6F\)
3. \(4F\) 4. \(F\)
Subtopic:  Young's modulus |
 76%
From NCERT
NEET - 2018
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The Young's modulus of steel is twice that of brass. Two wires of the same length and of the same area of cross-section, one of steel and another of brass are suspended from the same roof. If we want the lower ends of the wires to be at the same level, then the weight added to the steel and brass wires must be in the ratio of:

1. 1:2 2. 2:1
3. 4:1 4. 1:1
Subtopic:  Young's modulus |
 73%
From NCERT
NEET - 2015
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The Young's modulus of a wire is numerically equal to the stress at a point when:

1. the strain produced in the wire is equal to unity.
2. the length of the wire gets doubled.
3. the length increases by 100%.
4. All of these

Subtopic:  Young's modulus |
 73%
From NCERT
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A metallic rope of diameter \(1~ \text{mm}\) breaks at \(10 ~\text{N}\) force. If the wire of the same material has a diameter of \(2~\text{mm}\), then the breaking force is:

1. \(2.5~\text{N}\)  2. \(5~\text{N}\) 
3. \(20~\text{N}\)  4. \(40~\text{N}\) 

Subtopic:  Young's modulus |
 72%
From NCERT
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In the CGS system, Young's modulus of a steel wire is 2×1012 dyne/cm2. To double the length of a wire of unit cross-section area, the force required is:
1. 4×106 dynes
2. 2×1012 dynes
3. 2×1012 newtons
4. 2×108 dynes

Subtopic:  Young's modulus |
 73%
From NCERT
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On applying stress of \(20 \times 10^8~ ​​\text{N/m}^2\), the length of a perfectly elastic wire is doubled. It's Young’s modulus will be:

1. \(40 \times 10^8~ ​​\text{N/m}^2\) 2. \(20 \times 10^8~ ​​\text{N/m}^2\)
3. \(10 \times 10^8~ ​​\text{N/m}^2\) 4. \(5 \times 10^8~ ​​\text{N/m}^2\)
Subtopic:  Young's modulus |
 74%
From NCERT
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 The area of cross-section of a wire of length \(1.1\) m is \(1\) mm2. It is loaded with mass of \(1\) kg. If Young's modulus of copper is \(1.1\times10^{11}\) N/m2, then the increase in length will be: (If g=10 m/s2)

1. \(0.01\) mm 2. \(0.075\) mm
3. \(0.1\) mm 4. \(0.15\) mm
Subtopic:  Young's modulus |
 72%
From NCERT
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