A wire of length \(L\), area of cross section \(A\) is hanging from a fixed support. The length of the wire changes to \(\mathrm{L}_1\)when mass \(M\) is suspended from its free end. The expression for Young's modulus is:

1. \(\frac{{Mg(L}_1-{L)}}{{AL}}\) 2. \(\frac{{MgL}}{{AL}_1}\)
3. \(\frac{{MgL}}{{A(L}_1-{L})}\) 4. \(\frac{{MgL}_1}{{AL}}\)

Subtopic:  Young's modulus |
 78%
From NCERT
NEET - 2020
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NEET 2023 - Target Batch - Aryan Raj Singh
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The stress-strain curves are drawn for two different materials \(X\) and \(Y.\) It is observed that the ultimate strength point and the fracture point are close to each other for material \(X\) but are far apart for material \(Y.\) We can say that the materials \(X\) and \(Y\) are likely to be (respectively):

1. ductile and brittle
2. brittle and ductile
3. brittle and plastic
4. plastic and ductile
Subtopic:  Stress - Strain Curve |
 81%
From NCERT
NEET - 2019
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When a block of mass \(M\) is suspended by a long wire of length \(L\), the length of the wire becomes (\(L+l\)). The elastic potential energy stored in the extended wire is:
1. \(\frac{1}{2}MgL\)
2. \(Mgl\)
3. \(MgL\)
4. \(\frac{1}{2}Mgl\)

Subtopic:  Potential energy of wire |
 68%
From NCERT
NEET - 2019
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Given below are two statements: 
Assertion (A): The stretching of a spring is determined by the shear modulus of the material of the spring.
Reason (R): A coil spring of copper has more tensile strength than a steel spring of the same dimensions.
 
1. Both (A) and (R) are true and (R) is the correct explanation of (A).
2. Both (A) and (R) are true but (R) is not the correct explanation of (A).
3. (A) is false but (R) is true.
4. (A) is true but (R) is false.
Subtopic:  Shear and bulk modulus |
From NCERT
NEET - 2022
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Let a wire be suspended from the ceiling (rigid support) and stretched by a weight \(W\) attached at its free end. The longitudinal stress at any point of cross-sectional area \(A\) of the wire is:
1. zero
2. \(\frac{2W}{A}\)
3. \(\frac{W}{A}\)
4. \(\frac{W}{2A}\)
Subtopic:  Stress - Strain |
 66%
From NCERT
NEET - 2023
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The amount of elastic potential energy per unit volume (in SI unit) of a steel wire of length \(100\) cm to stretch it by \(1\) mm is: (Given: Young's modulus of the wire = \(2.0\times 10^{11}\) Nm-2)
1. \(10^{11}\) 2. \(10^{17}\)
3. \(10^{7}\) 4. \(10^{5}\)
Subtopic:  Potential energy of wire |
 64%
From NCERT
NEET - 2023
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