- 1(current)
Q. No.1. \(20\)
2. \(40\)
3. \(30\)
4. \(60\)
| 1. | \(\left ( \dfrac{{A}}{{B}}\right )^{1/5}\) | 2. | \(\left ( \dfrac{{B}}{{A}}\right )^{1/5}\) |
| 3. | \(\left ( \dfrac{{2A}}{{B}}\right )^{1/5}\) | 4. | \(\left ( \dfrac{{B}}{{2A}}\right )^{1/5}\) |
| 1. |  |
2. |  |
| 3. |  |
4. |  |
The potential energy (\(\mathrm U\)) of a diatomic molecule is a function dependent on \(\mathrm r\) (interatomic distance) as \(\mathrm{U}=\frac{\alpha}{\mathrm{r}^{10}}-\frac{\beta}{\mathrm{r}^5}-3\) where, \(\mathrm \alpha\) and \(\mathrm {\beta}\) are positive constants. The equilibrium distance between two atoms will be:
1. \(\left(\frac{2 \alpha}{\beta}\right)^{1 / 5}\)
2. \(\left(\frac{ \alpha}{\beta}\right)^{1 / 5}\)
3. \(\left(\frac{2 \alpha}{\beta}\right)^{2 / 5}\)
4. \(\left(\frac{ \alpha}{\beta}\right)^{2/ 5}\)
If the potential energy between two molecules is given by \(U = -\dfrac{A}{r^6}+ \dfrac{B}{r^{12}}, \) then the potential energy at equilibrium separation between molecules is:
| 1. | \(\dfrac{-A^{2}}{2B}\) | 2. | \(\dfrac{-A^{2}}{4B}\) |
| 3. | \(0\) | 4. | \(\dfrac{-A^{2}}{3B}\) |
A particle is moving along a circular path with a radius \(a,\) under the influence of an attractive force. The potential energy associated with the particle is given by: \(U=-\dfrac{k}{2r^2}.\)
The attractive force acting on the particle is:
| 1. | \(\dfrac{k}{4a^3}\) | 2. | \(\dfrac{k}{2a^3}\) |
| 3. | \(\dfrac{k}{a^3}\) | 4. | \(\dfrac{3k}{2a^3}\) |
(take potential energy \({=0}\) for \({r = 0)}\)
1. \({1\over 2}{\alpha r^3}\)
2. \({5\over 6}{\alpha r^3}\)
3. \({4\over 3}{\alpha r^3}\)
4. \({\alpha r^3}\)
- 1(current)
Q. No.
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