The kinetic energy of a particle continuously increases with time. It follows that:

1. its potential energy must decrease with time
2. the net force acting on it cannot be perpendicular to its path
3. the net force acting on it is along the velocity
4. friction cannot act on it
Subtopic:  Work Energy Theorem |
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Given below are two statements: 

Assertion (A): The net work done by gravity is equal to the loss in the vertical component of the kinetic energy for a projectile.
Reason (R): The work-energy theorem applies to all systems including projectiles.
 
1. Both (A) and (R) are True and (R) is the correct explanation of (A).
2. Both (A) and (R) are True but (R) is not the correct explanation of (A).
3. (A) is True but (R) is False.
4. (A) is False but (R) is True.
Subtopic:  Work Energy Theorem |
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A projectile is launched from a cliff of height \(h,\) with an initial speed \(u,\) at an angle \(\theta.\) The speed with which it hits the ground:

1. depends on the vertical component, \(u \text{sin}\theta\)
2. depends on the horizontal component, \(u \text{cos}\theta\)
3. depends on \(u,\) but not on \(\theta\)
4. depends on the quantity \(u \text{tan}\theta\)
Subtopic:  Work Energy Theorem |
From NCERT
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When a fan is switched on and it begins to rotate:

1. Its K.E. increases
2. Work is done by centrifugal force
3. Work is done by centripetal forces
4. Mechanical forces do not do any work
Subtopic:  Work Energy Theorem |
From NCERT
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A particle of mass '\(m\)' is released from the origin, and it moves under the action of a force: \(F(x)= F_0-kx\)
The maximum speed of the particle is, \(v= \)

1. \(\sqrt{\dfrac{F_0^2}{mk}}\) 2. \(\sqrt{\dfrac{2F_0^2}{mk}}\)
3. \(\sqrt{\dfrac{F_0^2}{2mk}}\) 4. \(2\sqrt{\dfrac{F_0^2}{mk}}\)
Subtopic:  Work Energy Theorem |
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