The potential energy function for a particle executing linear SHM is given by $\mathrm{V}\left(\mathrm{x}\right)=\frac{1}{2}{\mathrm{kx}}^2$ where k is the force constant of the oscillator (Fig). For k = 0.5 N/m, the graph of V(x) versus x is shown in the figure. A particle of total energy E turns back when it reaches $\mathrm{x}=\pm {\mathrm{x }}_{\mathrm{m}}$. If V and K indicate the PE and KE, respectively of the particle at $\mathrm{x}=+{\mathrm{x }}_{\mathrm{m}}$, then which of the following is correct?

1. V=0, K=E
2. V=E, K=0
3. V<E, K=0
4. V=0, K,E