A uniform chain of length \(L\) and mass \(M\) is lying on a smooth table and one-third of its length is hanging vertically down over the edge of the table. If \(g\) is the acceleration due to gravity, the work required to pull the hanging part on the table is:
1. \(MgL\)

2. \(\dfrac{MgL}{3}\)

3. \(\dfrac{MgL}{9}\)

4. \(\dfrac{MgL}{18}\)

Subtopic:  Gravitational Potential Energy |
 75%
Level 2: 60%+
Hints

premium feature crown icon
Unlock IMPORTANT QUESTION
This question was bookmarked by 5 NEET 2025 toppers during their NEETprep journey. Get Target Batch to see this question.
✨ Perfect for quick revision & accuracy boost
Buy Target Batch
Access all premium questions instantly

A particle of mass 'm' is moving in a horizontal circle of radius 'r' under a centripetal force equal to –K/r2, where K is a constant. The total energy of the particle will be:

1. K2r

2. K2r

3. Kr

4. Kr

Subtopic:  Potential Energy: Relation with Force |
 58%
Level 3: 35%-60%
Hints
Links

premium feature crown icon
Unlock IMPORTANT QUESTION
This question was bookmarked by 5 NEET 2025 toppers during their NEETprep journey. Get Target Batch to see this question.
✨ Perfect for quick revision & accuracy boost
Buy Target Batch
Access all premium questions instantly

A force \(F = -k(y\hat i +x\hat j)\) (where \(k\) is a positive constant) acts on a particle moving in the \(xy\text-\)plane. Starting from the origin, the particle is taken along the positive \(x\text-\)axis to the point \((a,0)\) and then parallel to the \(y\text-\)axis to the point \((a,a)\). The total work done by the force on the particle is:
1. \(-2ka^2\)
2. \(2ka^2\)
3. \(-ka^2\)
4. \(ka^2\)

Subtopic:  Work Done by Variable Force |
 58%
Level 3: 35%-60%
Hints
Links

advertisementadvertisement

premium feature crown icon
Unlock IMPORTANT QUESTION
This question was bookmarked by 5 NEET 2025 toppers during their NEETprep journey. Get Target Batch to see this question.
✨ Perfect for quick revision & accuracy boost
Buy Target Batch
Access all premium questions instantly

A lorry and a car moving with the same K.E. are brought to rest by applying the same retarding force, then:

1. Lorry will come to rest in a shorter distance

2. Car will come to rest in a shorter distance

3. Both will come to rest in a same distance

4. None of the above

Subtopic:  Work Energy Theorem |
 67%
Level 2: 60%+
Hints

The relationship between force and position is shown in the given figure (in a one-dimensional case). The work done by the force in displacing a body from \(x = 1~\text{cm}\) to \(x = 5~\text{cm}\) is:
      
1. \(20~\text{ergs}\) 
2. \(60~\text{ergs}\)
3. \(70~\text{ergs}\) 
4. \(700~\text{ergs}\)

Subtopic:  Work Done by Variable Force |
 85%
Level 1: 80%+
Hints
Links

premium feature crown icon
Unlock IMPORTANT QUESTION
This question was bookmarked by 5 NEET 2025 toppers during their NEETprep journey. Get Target Batch to see this question.
✨ Perfect for quick revision & accuracy boost
Buy Target Batch
Access all premium questions instantly

The graph between the resistive force \(F\) acting on a body and the distance covered by the body is shown in the figure. The mass of the body is \(25\) kg and the initial velocity is \(2\) m/s. When the distance covered by the body is \(4\) m, its kinetic energy would be:

   
1. \(50\) J
2. \(40\) J
3. \(20\) J
4. \(10\) J

Subtopic:  Work Done by Variable Force |
 56%
Level 3: 35%-60%
Hints
Links

advertisementadvertisement

The relationship between the force \(F\) and the position \(x\) of a body is as shown in the figure. The work done in displacing the body from \(x = 1\text{ m}\) to \(x = 5\text{ m}\) will be:


1. \(30\text{ J}\)
2. \(15\text{ J}\)
3. \(25\text{ J}\)
4. \(20\text{ J}\)

Subtopic:  Work Done by Variable Force |
 55%
Level 3: 35%-60%
Hints
Links

A particle moves from a point \((-2\hat i+5\hat j)~\text{to}~(4\hat j +3\hat k)\) when a force of \((4\hat i +3\hat j)~\text{N}\) is applied. How much work has been done by the force?
1. \(8~\text{J}\)
2. \(11~\text{J}\)
3. \(5~\text{J}\)
4. \(2~\text{J}\)
Subtopic:  Work done by constant force |
 71%
Level 2: 60%+
NEET - 2016
Hints
Links

A block of mass \(10\) kg, moving in the \(x\text-\)direction with a constant speed of \(10\) ms-1, is subjected to a retarding force \(F=0.1x \) J/m during its travel from \(x =20\) m to \(30\) m. Its final kinetic energy will be:

1. \(475\) J 2. \(450\) J
3. \(275\) J 4. \(250\) J
Subtopic:  Work Done by Variable Force |
 74%
Level 2: 60%+
NEET - 2015
Hints
Links

advertisementadvertisement

premium feature crown icon
Unlock IMPORTANT QUESTION
This question was bookmarked by 5 NEET 2025 toppers during their NEETprep journey. Get Target Batch to see this question.
✨ Perfect for quick revision & accuracy boost
Buy Target Batch
Access all premium questions instantly

A ball is thrown vertically downwards from a height of \(20\) m with an initial velocity \(v_0\). It collides with the ground, loses \(50\%\) of its energy in a collision and rebounds to the same height. The initial velocity \(v_0\) is: (Take \(g = 10~\text{m/s}^2\))
1. \(14~\text{m/s}\)
2. \(20~\text{m/s}\)
3. \(28~\text{m/s}\)
4. \(10~\text{m/s}\)

Subtopic:  Conservation of Mechanical Energy |
 66%
Level 2: 60%+
NEET - 2015
Hints
Links