A particle is moving in a circle of radius \(r\) under the action of a force \( F = α r^ 2 \) which is directed towards centre of the circle. The total mechanical energy (kinetic energy + potential energy) of the particle is:
(take potential energy \({=0}\) for \({r = 0)}\) 
1. \({1\over 2}{\alpha r^3}\)
2. \({5\over 6}{\alpha r^3}\)
3. \({4\over 3}{\alpha r^3}\)
4. \({\alpha r^3}\)
Subtopic:  Potential Energy: Relation with Force |
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A particle is moving along a circular path with a radius \(a,\) under the influence of an attractive force. The potential energy associated with the particle is given by: \(U=-\dfrac{k}{2r^2}.\)
The attractive force acting on the particle is:

1. \(\dfrac{k}{4a^3}\) 2. \(\dfrac{k}{2a^3}\)
3. \(\dfrac{k}{a^3}\) 4. \(\dfrac{3k}{2a^3}\)
Subtopic:  Potential Energy: Relation with Force |
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If the potential energy between two molecules is given by \(U = -\dfrac{A}{r^6}+ \dfrac{B}{r^{12}}\)
then the potential energy at equilibrium separation between molecules is:

1. \(\dfrac{-A^{2}}{2B}\) 2. \(\dfrac{-A^{2}}{4B}\)
3. \(0\) 4. \(\dfrac{-A^{2}}{3B}\)
Subtopic:  Potential Energy: Relation with Force |
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Potential energy as a function of \({r}\) is given by; \({U}=\dfrac{{A}}{{r}^{10}}-\dfrac{{B}}{{r}^5},\) where \({r}\) is the interatomic distance, and \({A}\) and \({B}\) are positive constants. The equilibrium distance between the two atoms will be: 
1. \(\left ( \dfrac{{A}}{{B}}\right )^{1/5}\) 2. \(\left ( \dfrac{{B}}{{A}}\right )^{1/5}\)
3. \(\left ( \dfrac{{2A}}{{B}}\right )^{1/5}\) 4. \(\left ( \dfrac{{B}}{{2A}}\right )^{1/5}\)
Subtopic:  Potential Energy: Relation with Force |
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The potential energy function corresponding to a conservative force is given as \(U(x, y, z)=\frac{3 x^2}{2}+5 y+6 z,\) then the force at \({x}=6\) is \(P~\text{N}.\) The value of \(P\) up to its nearest integral value is:
1. \(20\)
2. \(40\)
3. \(30\)
4. \(60\)
Subtopic:  Potential Energy: Relation with Force |
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