A point mass 'm' is moved in a vertical circle of radius 'r' with the help of a string. The velocity of the mass is 7gr at the lowest point. The tension in the string at the lowest point will be:

1. 6 mg

2. 7 mg

3. 8 mg

4. 1 mg

Subtopic:  Non Uniform Vertical Circular Motion |
 75%
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A mass m is attached to a thin wire and whirled in a vertical circle. The wire is most likely to break when:

1. inclined at a 60° angle from vertical

2. the mass is at the highest point

2. the wire is horizontal

4. the mass is at the lowest point.

Subtopic:  Non Uniform Vertical Circular Motion |
 76%
NEET - 2019
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A particle of mass ‘m’ having speed v goes in a vertical circular motion such that its centre is at its origin, as shown in the figure. If at any instant the angle made by the string with a negative y-axis is θ then the tension in the string is:
[Take radius = R]

1. mgsinθ+mv2R
2.mgcosθ-mv2R
3.mgcosθ+mv2R
4.mgsinθ-mv2R

Subtopic:  Non Uniform Vertical Circular Motion |
 64%
From NCERT
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A bucket full of water tied with the help of a 2 m long string performs a vertical circular motion. The minimum angular velocity of the bucket at the uppermost point so that water will not fall will be:

1. 25 rad/s

2. 5 rad/s

3. 5 rad/s

4. 10 rad/s

Subtopic:  Non Uniform Vertical Circular Motion |
 56%
From NCERT
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The kinetic energy 'K' of a particle moving in a circular path varies with the distance covered S as K = aS2, where a is constant. The angle between the tangential force and the net force acting on the particle is: (R is the radius of the circular path)

1.  tan-1SR

2.  tan-1RS

3.  tan-1aR

4.  tan-1Ra

Subtopic:  Non Uniform Vertical Circular Motion |
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A stone of mass \(\mathrm{m}\) tied to the end of a string revolves in a vertical circle of radius \(\mathrm{R}.\) The net forces at the lowest and highest points of the circle directed vertically downwards are:

Lowest point Highest point
1. \(\mathrm{mg}-\mathrm{T_1}\) \(\mathrm{mg}+\mathrm{T_2}\)
2. \(\mathrm{mg}+\mathrm{T_1}\) \(\mathrm{mg}+\mathrm{T_2}\)
3. mg+T1-mv12R mg-T2+mv22R
4. mg-T1-mv12R mg+T2+mv22R

(T1 and v1 denote the tension and speed at the lowest point.T2 and v2 denote corresponding values at the highest point.)

Subtopic:  Non Uniform Vertical Circular Motion |
From NCERT
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The angle between the position vector and the acceleration vector of a particle in non-uniform circular motion (centre of the circle is taken as the origin) will be:

1. 0°

2. 45°

3. 75°

4. 135°

Subtopic:  Non Uniform Vertical Circular Motion |
From NCERT
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