Calculate the maximum acceleration of a moving car so that a body lying on the floor of the car remains stationary. The coefficient of static friction between the body and the floor is \(0.15\) (Take \(g=10\) ms-2).
1.  \(50\) ms-2 2.  \(1.2\) ms-2
3.  \(150\) ms-2 4.  \(1.5\) ms-2
Subtopic:  Friction |
 79%
From NCERT
NEET - 2023
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A block of mass \(2\) kg is placed on inclined rough surface \(AC\) (as shown in the figure) of coefficient of friction \(\mu.\) If \(g=10\) ms-1, the net force (in N) on the block will be:
                    
1. \(10\sqrt3\) 2. zero
3. \(10\) 4. \(20\)
Subtopic:  Friction |
 64%
From NCERT
NEET - 2023
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Calculate the acceleration of the block and trolly system shown in the figure. The coefficient of kinetic friction between the trolly and the surface is \(0.05\).
\(g=10 \mathrm{~m} / \mathrm{s}^2\), mass of the string is negligible and no other friction exists ). 

           
1. \( 1.25 \mathrm{~m} / \mathrm{s}^2 \)
2. \( 1.50 \mathrm{~m} / \mathrm{s}^2 \)
3. \( 1.66 \mathrm{~m} / \mathrm{s}^2 \)
4. \( 1.00 \mathrm{~m} / \mathrm{s}^2\)

Subtopic:  Friction |
 65%
From NCERT
NEET - 2020
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NEET 2023 - Target Batch - Aryan Raj Singh
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A body of mass \(m\) is kept on a rough horizontal surface (coefficient of friction =\(\mu)\). A horizontal force is applied to the body, but it does not move. The resultant of normal reaction and the frictional force acting on the object is given by \(\vec F\) where:
1. \(|{\vec F}| = mg+\mu mg\)
2. \(|\vec F| =\mu mg\)
3. \(|\vec F| \le mg\sqrt{1+\mu^2}\)
4. \(|\vec F| = mg\)

Subtopic:  Friction |
 73%
From NCERT
NEET - 2019
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NEET 2023 - Target Batch - Aryan Raj Singh
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